/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 9.16 Calculate the number of equivale... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Calculate the number of equivalents in each of the following:

a.1mole ofMg2+

b.0.5mole ofH+

c.4molesofCl-

d.2molesofFe3+

Short Answer

Expert verified

(part a) The number of equivalents in1moleofMg2+=2eq

(part b) The number of equivalents in 0.5moleofH+=0.5eq

(part c) The number of equivalents in 4molesofCl-=4eq

(part d) The number of equivalents in2molesofFe3+=6eq

Step by step solution

01

Introduction (part a).

In a chemical process, an equivalent has been the quantity of one material that people react to (or is equivalent to) an arbitrarily defined quantity of another compound. The mass of an equivalent is equivalent to its weight.

02

Given Information (part a).

Given:

1mole ofMg2+

03

Explanation (part a). 

To compute the value of equivalents.

Each mole has two equivalents for such an ion with a charge of 2+.Thus the,

1moleofMg2+=2eq

04

Given Information (part b). 

Given:

0.5mole ofH+

05

Explanation (part b). 

To compute the value of equivalents.

Each mole contains a single equivalent for just an ion with a charge of +.Therefore,

0.5moleofH+=0.5eq

06

Given Information (part c). 

Given:

4molesofCl-

07

Explanation (part c). 

To compute the value of equivalents.

Every mole uses a single equivalent for an ion with a charge of -.Thus,

4molesofCl-=4eq

08

Given Information (part d). 

Given:

2molesofFe3+
09

Explanation (part d).

To compute the value of equivalents.

There's really one equivalent with each mole of an ion with a charge of -.Consequently,

2molesofFe3+=6eq

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.