91Ó°ÊÓ

(a) Water is healed to$145°F$

(a) Hot water temperature in Fahrenheit is$145°F$.
The temperature scale and Fahrenheit scale are related as follows:

$F=\frac{9}{5}\left(C\right)+32$

Substitute the worth of degree Fahrenheit to search out the worth in degree.

${}^{∘}\mathrm{C}=\frac{5}{9}\left({}^{∘}\mathrm{F}−32\right)$

$=\frac{5}{9}\left({145}^{∘}\mathrm{F}−32\right)$

$=\frac{5}{9}(113{)}^0\mathrm{C}$

$={62.7}^{∘}\mathrm{C}$

Thus, the temperature $145°F$ is adore the temperature $62.7°C$.

Extreme Hypothermia Child's temperature dropped to$20°C$

(b) Body temperature in degree Centigrade is$20.6°C$
The relationship between temperature scale and Celsius scale is as follows:

$F=\frac{9}{5}\left(C\right)+32$

Substitute the worth of degree Celsius to seek out the worth in Fahrenheit.

$F=\frac{9}{5}\left(C\right)+32$

$=\frac{9}{5}\left(20.6\mathrm{C}\right)+32$

$=185.4+32$

$=217.4°F$

Thus, the temperature$20.6°C$ is reminiscent of the temperature $217.4°F$.