91影视

We need to identify the group number of$X_2{O}_3$.

Consider:$X_2{O}_3$

ion of oxygen $\left(O\right)鈥�鈥�鈥�O^{2-}$say change of $X$is $x$then by charge balance -

$$\begin{gathered} 2x+3(2-)=0 \\ x=+3 \end{gathered}$$

Therefore, ion of $x鈥�鈥�鈥�X^{3+}$

Here, three electrons are donated to achieve octect so group is$3A\left(13\right)$.

We need to identify the group number of$X_{2}S{O}_3$.

Consider: $X_{2}S{O}_3$

ion of Sulfite $鈥�鈥�鈥�{So}_3^{2-}$charge of $X$is $x$then by charge balance -

$$\begin{gathered} 2x+(2-)=0 \\ x=1+ \end{gathered}$$

Therefore, the ion of $x鈥�鈥�鈥�X^{+}$

Here,

An electron donated to achieve octect so group isrole="math" localid="1652437478196" $1A\left(1\right)$.

We need to identify the group number of$N{a}_{3}X$.

Consider: $N{a}_{3}X$

ion of Sodium $\left(Na\right)$$鈥�鈥�鈥�N{a}^{+}$charge of $X$is $x$then by charge balance -

$$\begin{gathered} x+3\left(1+\right)=0 \\ x=3- \end{gathered}$$

Therefore, the ion of $x鈥�鈥�鈥�X^{3-}$

Three electron accepted to achieve octect so the group is$5A\left(15\right)$.