Q. 11.50 Give the IUPAC name (including c... [FREE SOLUTION]

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Chapter 11: Q. 11.50 (page 393)

Give the IUPAC name (including cis or trans, if needed) for each of the following:

Short Answer

Expert verified

Part(a) IUPAC name is $2 - M e t h y l p e n t e n e$

Part(b) IUPAC name is $3 - M e t h y l c y c l o h e x e n e$

Part(c) IUPAC name is $C i s - H e x - 2 - e n e$

Step by step solution

Part(a) Step 1 : Given information

We need to find IUPAC name of compound .

Part(a) Step 2 : Simplify

We are given a compound having five carbons with one double bond and one methyl group at second carbon as substituent. So according to IUPAC rules , the name of compound should end with "ene" due to double bond and starts with suffix "Pent" due to five carbons.

Hence,

IUPAC name is $2 - M e t h y l p e n t e n e$

Part(b) Step 1 : Given information

We need to find IUPAC name of compound

Part(b) Step 2 : Simplify

We are given a compound having six carbons with one double bond in cyclic structure and one methyl group at third carbon as substituent. So according to IUPAC rules , the name of compound should end with "ene" due to double bond and starts with suffix "hex" due to six carbons with "cyclo" due to cyclic structure.

Hence,

IUPAC name is $3 - M e t h y l c y c l o h e x e n e$

Part(c) Step 1 : Given information

We need to find IUPAC name of compound

Part(c) Step 2 : Simplify

We are given a compound having six carbons with one double bond in cis form. So according to IUPAC rules , the name of compound should end with "ene" due to double bond and starts with suffix "Hex" due to six carbons with "cis" .

Hence,

IUPAC name is $C i s - H e x - 2 - e n e$