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Chapter 8: Q. 8.84 (page 283)

In the fermentation of glucose (winemaking), $780 m L$ of $C O_{2}$ gas was produced at $37 掳 C$ and $1.00 a t m$ . What is the final volume, in liters, of the gas when measured at $22 掳 C$ and $675 m m H g$ . If the amount of gas does not change? $(8.5)$

Short Answer

Expert verified

The final volume is $0.83 L$ .

Step by step solution

01

Given Information

We need to find the final volume.

02

Simplify

Initial conditions as;

$P_{1} = 1 a t m V_{1} = 780 m L = 0.78 L T_{1} = 37 掳 C = (37 - 273) K = 310 K$

Final conditions as:

$P_{2} = 675 m m H g = 0.89 a t m T_{2} = 22 掳 C = (22 + 273) K = 295 K$

Now, calculating the final volume $V_{2}$ :

$\frac{P V}{T} = C o n s \tan t V_{2} = \frac{P_{1} 脳 V_{1} 脳 T_{2}}{T_{1} 脳 P_{2}} V_{2} = \frac{1 a t m 脳 0.78 L 脳 295 K}{310 K 脳 0.89 a t m} = 0.83 L$

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Most popular questions from this chapter

Calculate the final pressure, in atmospheres, for each of the following, if $V$ and $n$ do not change:

a. A gas with an initial pressure of $1.20 a t m$ at $75 掳 C$ is cooled to $- 32 掳 C .$

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