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A sample of Ar gas has a volume of 5.40 L with an unknown pressure. The gas has a volume of 9.73 L when the pressure is 3.62 atm, with no change in temperature or amount of gas. What was the initial pressure, in atmospheres, of the gas?

Short Answer

Expert verified

The initial pressure of the gas was6.52atm.

Step by step solution

01

Given information

We need to find the initial pressure of the gas

02

Explanation

We can apply Boyle's law as the temperature is constant

P1V1=P2V2

Now,

V1=5.40L

P2=3.62atm

localid="1653571753412" V2=9.73L

Substituting the values we get,

localid="1653571801708" role="math" P1=3.62atm×9.73L5.40L=6.52atm

So the initial pressure of the gas was6.52atm

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