91Ó°ÊÓ

The melting point of benzene =$5.5^{o}C$

The boiling point of benzene =$80.1^{o}C$

The graph is,

As per the temperature information given, the heating bend of benzene in the temperature range $0^{∘}\mathrm{C}\text{to}{100}^{∘}\mathrm{C}$is drawn and from the bend, it is seen that the substance stays in a solid state up to and it began to liquefy at this temperature.

Subsequently at ${15}^{o}C$it will be in a liquid state.

At the melting point of any substance, the heating bend stays parallel to the x-axis for example heat added as the temperature of the substance stays unaltered until entire the mass of the substance is melted.

It will be in a liquid form at${63}^{∘}\mathrm{C}$as the melting point of benzene is${5.5}^{∘}\mathrm{C}$after which it turns liquid.

It will be in a gaseous form at ${98}^{o}C$as after reaching the boiling point it turns gaseous and the boiling point of benzene is${80.1}^{∘}\mathrm{C}$

Both liquid and gas be present at ${80.1}^{∘}\mathrm{C}$as both the states are present together as represented with a parallel line with the x-axis.