91Ó°ÊÓ

The given is the weight of a solid object that is submerged in the water

The objective is to find the density of the solid object submerged in the water

Any substance's density is defined as the ratio of mass to volume. As a result, a substance's density is an inherent attribute.

The solid object of $8.24g$ is submerged in the graded cylinder containing water in this problem. $18.5mL$ is the initial volume of water in the cylinder. After immersing an object, the volume of water is $23.1mL$.

A given object's mass is $8.24g$

$$\begin{gathered} Volumeincreasedbysubmerging=Finalvolume-Initialvolume \\ =23.1-18.5 \\ =4.6mL \end{gathered}$$

The object's mass is $8.24g$with three significant figures, whereas its volume is $4.6mL$with two significant numbers. When performing this computation, we must take into account significant figure calculation criteria.

Density of solid object $=\frac{\text{mass in}\mathrm{g}}{\text{volume in}\mathrm{mL}}$

$$\begin{gathered} =\frac{8.24g}{4.6mL} \\ =1.79gmL \end{gathered}$$

The denominator, on the other hand, has two significant figures, hence the answer should also have two significant figures.

As a result, the answer is The solid object's density.$1.8g/mL$

The solid item submerged in water has a density of