91Ó°ÊÓ

We need to find number of moles of $\mathrm{C}$in $0.185$moles of${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$

One mole of ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$contains $6$moles of $\mathrm{C}$

So, moles of $\mathrm{C}$in $0.185$moles of ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$= $6×0.185=1.11$

Hence, $1.11$ moles of carbon present in $0.185$ moles of${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$

We need to find number of moles of $\mathrm{O}$in $0.185$moles of ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$

One mole of ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$contains one mole of oxygen

So, moles of oxygen in $0.185$moles of ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$= $0.185×1=0.185$

Hence,$0.185$ moles of oxygen is present in $0.185$moles of ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$.

We need to find number of atoms of $\mathrm{H}$in $0.185$moles of${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$

One mole of ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$contains $14$mole of $\mathrm{H}$in it.

Number of atoms of $\mathrm{H}$in $0.185$moles of${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$ =$0.185×4×6.02×{10}^{23}=4.4×{10}^{22}$

Hence, $4.4×{10}^{22}$atoms are present.

We need to find number of atoms of $\mathrm{C}$in $0.185$moles of${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$

One mole of ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$ contains $6$mole of $\mathrm{C}$in it.

Number of atoms of $\mathrm{C}$in $0.185$moles of data-custom-editor="chemistry" ${\mathrm{C}}_6{\mathrm{H}}_{14}\mathrm{O}$= $$\begin{gathered} 0.185×6×6.02×{10}^{23} \\ =6.68×{10}^{23} \end{gathered}$$

Hence, $6.68×{10}^{23}$ atoms are present.