91Ó°ÊÓ

We have to calculate the molar mass of ${\mathrm{AlF}}_3$

We know that,

Molar mass of one Al atom =$26.98\mathrm{g}$

Molar mass of one $\mathrm{F}$ atom = localid="1653486093381" $18.99\mathrm{g}$

So, molar mass of ${\mathrm{AlF}}_3$=$26.98+3\left(18.99\right)$=localid="1653486102791" $83.95\mathrm{g}$

We have to calculate the molar mass of ${\mathrm{C}}_2{\mathrm{H}}_4{\mathrm{Cl}}_2$

We know that,

Molar mass of one $\mathrm{C}$atom =localid="1653486146025" $12.01\mathrm{g}$

Molar mass of one $\mathrm{H}$ atom =localid="1653486137281" $1.00\mathrm{g}$

Molar mass of one$\mathrm{Cl}$atom =localid="1653486126084" $35.45\mathrm{g}$

So, molar mass of ${\mathrm{C}}_2{\mathrm{H}}_4{\mathrm{Cl}}_2$=$2\left(12.01\right)+4\left(1.00\right)+2\left(35.45\right)$=localid="1653486117214" $98.92\mathrm{g}$

We have to calculate the molar mass of ${\mathrm{SnF}}_2$

We know that,

Molar mass of one $\mathrm{Sn}$atom =localid="1653486171774" $118.69\mathrm{g}$

Molar mass of one $\mathrm{F}$atom =localid="1653486181350" $18.99\mathrm{g}$

So, molar mass of ${\mathrm{SnF}}_2$=$118.69+2\left(18.99\right)$=localid="1653486190956" $156.67\mathrm{g}$