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Pentane gas, C5H12, undergoes combustion with oxygen gas to produce carbon dioxide and water gases. (7.4,7.8)

a. Write the balanced chemical equation.

b. How many grams of C5H12are needed to produce localid="1653472797651" 72gof water?

c. How many grams of CO2are produced from localid="1653472811626" 32.0gof O2?

Short Answer

Expert verified

(a) The required balanced equation isC5H12+8O2→∆5CO2+6H2O+energy

(b) The localid="1653472833201" 48gof pentane gas is needed to produce localid="1653472847302" 72gof water

(c) The localid="1653472861523" 27.5gof CO2are produced from localid="1653472874083" 32gof O2

Step by step solution

01

Part (a) Step 1: Given information

We need to find the balanced equation

02

Part (a) Step 2: Explanation 

We know that

The balanced equation is that in which the total mass of reactants is equal to the total mass of products.

Therefore, The balanced equation is,

C5H12+8O2→∆5CO2+6H2O+energy

03

Part (b) Step 1: Given information 

We need to find the mass of pentane gas needed to produce 72gof water

04

Part (b) Step 2: Explanation

From part (a)

We know that

The 108gof water is produced by 72gof pentane gas

Therefore,72gof water is produced by72g108g×72g=48gof pentane gas

05

Part (c) Step 1: Given information

We need to find mass ofCO2produced from 32gof O2

06

Part (c) Step 2: Explanation  

From part (a)

We know that

The 256gof O2produces 220of CO2

Therefore, localid="1653473147345" 32gofO2produceslocalid="1653485137564" 220g256g×32g=27.5gofCO2

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