/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q.10.104 Identify the conjugate acid-base... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Identify the conjugate acid-base pairs in each of the following equations:

a.HNO2(aq)+HS−(aq)⇄NO2−(aq)+H2S(g)

b.HCl(aq)+OH−(aq)⟶Cl−(aq)+H2O(l)

Short Answer

Expert verified

Part (a) . HS−(aq)→H2S(aq)and HCl(aq)→Cl−(aq)

Part (b) . H2O(l)→OH−(aq)and HNO2(aq)→NO2−(aq)

Step by step solution

01

Given Information (Part a)

In the Brønsted-Lowry meaning of acids and bases, a conjugate acid-base pair comprises two substances that vary exclusively by the presence of a proton. A conjugate acid is framed when a proton is added to a base, and a conjugate base is shaped when a proton is eliminated from an acid.

02

Explanation Part (a)

A conjugate acid is framed when a proton is added to a base, and a conjugate base is shaped when a proton is eliminated from an acid.

Hence,

the conjugate acid-base pairs are,

HS−(aq)→H2S(aq)andHCl(aq)→Cl−(aq)

03

Explanation Part (b)

A conjugate acid is framed when a proton is added to a base, and a conjugate base is shaped when a proton is eliminated from an acid.

Hence,

the conjugate acid-base pairs are,

H2O(l)→OH−(aq)andHNO2(aq)→NO2−(aq)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.