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Chapter 10: Q. 10.96 (page 360)

A 10.0-mL sample of vinegar, which is an aqueous solution of acetic acid, ${HC}_{2} H_{3} O_{2}$ , requires $16.5 mL$ of a $0.500 MNaOH$ solution to reach the endpoint in a titration. What is the molarity of the acetic acid solution? $(10.7)$
${HC}_{2} H_{3} O_{2} (a q) + NaOH (a q) 鉄� H_{2} O (f) + {NaC}_{2} H_{3} O_{2} (a q)$

Short Answer

Expert verified

Molarity ${CH}_{3} COOH = \frac{0.0083 {moleCH}_{3} COOH}{0.010 L}$

$= 0.830 {MCHCOOH}_{3} OOH$

Step by step solution

01

Given information

That are given numbers are calculated by:

Equalities /conversion factors

02

Explanation

Step 1 Given $16.5 ml$ of $0.500 MNaOH; 10.0 {mlCH}_{3} COOH = 0.010 {LCH}_{3} COOH$

Need molarity of ${CH}_{3} COOH$ .

Step 2 Plan

Metric Molarity mole Divide by

localid="1654585928067" $16.5 mlL$ moles $NaOH$ mole ${CH}_{3} COOHM$

Factor factor factor liters

Step 3 Equalities/conversion factors

$\begin{aligned} 1 L NaOH = 0.500 moleNaOH \\ \frac{1 L}{0.500 mole} = \frac{0.500 mole}{1 L} \\ 1 L NaOH = 1000 mlNaOH \\ \frac{1 L}{1000 ml} = \frac{1000 ml}{1 L} \end{aligned}$

03

Given information

That are given equations are:

04

Explanation

Step 2 of 2

l mole $NaOH = 1 {moleCHCOOH}_{3} COOH$

Step 4 Set up problem

$16.5 mLNaOH 脳 \frac{1 L SaOH}{1000 mLNaOH} 脳 \frac{0.500 mole . AaOH}{1 LNeOH} 脳 \frac{1 {moleCHCOOH}_{3}}{1 moleNaOH}$

$= 0.0083 {moleCHCHOH}_{3} OOH$

Molarity ${CH}_{3} COOH = \frac{0.0083 {moleCH}_{3} COOH}{0.010 L}$

$= 0.830 {MCH}_{3} COOH$

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Most popular questions from this chapter

What is the meaning and value of $K_{w}$ ?

Write the formula for the conjugate base for each of the following acids:

a. ${HCO}_{3}$

b. ${CH}_{3} {NH}_{3}^{+}$

c. ${HPO}_{4}^{2 -}$

d. ${HNO}_{2}$

Solution X has a pH of 9.0, and solution Y has a pH of 7.0.

a. Which solution is more acidic?

b. What is the $[H_{3} O^{+}]$ in each?

c. What is the $O H^{-}$ in each?

In Larry's esophageal pH test, a pH value of 3.60 was recorded in the esophagus. What is the $[H_{3} O^{+}]$ in his esophagus?

Using Table $10.3$ , identify the stronger acid in each of the following pairs:

a. $HBr$ or ${HNO}_{2}$

b. $H_{3} {PO}_{4}$ or ${HSO}_{4}^{-}$

c. $HCN$ or $H_{2} {CO}_{3}$

See all solutions

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