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Chapter 10: Q. 10.66 (page 355)

After Larry had taken Nexium for 4 weeks, the pHin his stomach was raised to 4.52. What is the H3O+in his stomach?

Short Answer

Expert verified

TheH3O+concentration in stomach is3.02脳10-5M

Step by step solution

01

Step - 1  Given information

  • The pH of a solution can be calculated using the negative logarithmic base value 10 is the H3O+focus.

pH=-logH3O+

pOH=-logOH-

pH+pOH=14

02

Step - 2   Explanation

  • The elevated pH in the stomach is 4.52. Calculate the Using the following formula, calculate the H3O*concentration:

pH=-logH3O+

4.52=-logH3O+

H3O*=10(-4.52)

H3O*=3.02脳10-5M

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Most popular questions from this chapter

Identify the reactant that is a Br酶nsted-Lowry acid and the reactant that is a Br酶nsted-Lowry base in each of the following:

a.HI(aq)+H2O(l)鉄�I-(aq)+H3O+(aq)

b.F-(aq)+H2O(l)鈬�HF(aq)+OH-(aq)

If a base is added to pure water, why does the H3O+decrease?

State whether each of the following solutions is acidic, basic. or neutral: (10.6)

a. rain, pH 5.2

b. tears, pH7.5

c. tea, pH3.8

d. cola, pH 2.5

e. photo developer, pH12.0

Write the formula for the conjugate base for each of the following acids:

a.HF

b.H2O

c.H2PO3-

d.HSO4-

At rest, the H3O+of the stomach fluid is 2.0脳10-4M. What is thepH of the stomach fluid?
See all solutions

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