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In the reversible adiabatic expansion of an ideal monoatomic gas, the final volume is 8 times the initial volume. The ratio of final temperature to initial temperature is (a) \(8: 1\) (b) \(1: 4\) (c) \(1: 2\) (d) \(4: 1\)

Short Answer

Expert verified
The ratio of final temperature to initial temperature is 1:4, hence the correct option is (b) 1:4.

Step by step solution

01

Recall the relationship for adiabatic processes

For a reversible adiabatic expansion of an ideal monoatomic gas, the relationship between the volumes and temperatures is given by the adiabatic law, which can be expressed as TV^(γ-1) = constant, where T is the temperature, V is the volume, and γ (gamma) is the heat capacity ratio (Cp/Cv), which is 5/3 for an ideal monoatomic gas.
02

Set up the ratio using initial and final states

Let the initial volume be V_i and the initial temperature be T_i. After expansion, the final volume V_f is 8 times V_i and the final temperature is T_f. Using the adiabatic law, we can write T_i V_i^(γ-1) = T_f V_f^(γ-1).
03

Substitute the known values and solve for the temperature ratio

Substitute V_f = 8V_i into the equation and solve for T_f/T_i: T_i V_i^(γ-1) = T_f (8V_i)^(γ-1), which simplifies to T_f/T_i = (V_i/V_f)^(γ-1) = (1/8)^(5/3-1) = (1/8)^(2/3).
04

Calculate the value of the ratio

Calculate the temperature ratio as (1/8)^(2/3) = (1/8)^(0.666...), which is equal to 1/4 when simplified.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reversible Adiabatic Expansion
Understanding an adiabatic process is essential when studying thermodynamics in physical chemistry, especially when delving into how ideal gases behave under certain conditions. A reversible adiabatic expansion is a particular type of process in which a gas expands, doing work on its surroundings, without the exchange of heat with its environment.

This process is both reversible, meaning it can be returned to its initial state without losing energy, and adiabatic, indicating there is no heat transfer. During such an expansion, energy is conserved within the system, which causes the temperature of the gas to decrease as it does work on the surroundings.

The connection between temperature and volume during this process is depicted by a simple yet significant formula: \( TV^{(\gamma-1)} = \text{constant} \), where \(T\) is temperature, \(V\) is volume, and \(\gamma\) is the heat capacity ratio. The decrease in temperature is a direct consequence of the energy conversion from internal energy to work without the addition of external heat.
Heat Capacity Ratio
The heat capacity ratio, denoted by \(\gamma\) (gamma), is a pivotal term in thermodynamics, particularly when studying adiabatic processes. It is the ratio of the specific heat capacity at constant pressure \(C_p\) to that at constant volume \(C_v\), and is given by \(\gamma = C_p/C_v\).

For an ideal monoatomic gas, the value of \(\gamma\) is usually 5/3 or approximately 1.67. This value is important because it influences how much the temperature of the gas changes with volume during an adiabatic process. A higher \(\gamma\) means the temperature of the gas will drop more sharply with an increase in volume during an adiabatic expansion.

It is this ratio that we use in the formula \( TV^{(\gamma-1)} = \text{constant} \) to determine the relationship between temperature and volume changes within an adiabatic process. In our exercise, recognizing the correct heat capacity ratio is integral to solving for the final temperature in relation to the initial temperature after expansion.
Ideal Monoatomic Gas
An ideal monoatomic gas is a theoretical simplification often used in physics and chemistry to study gas behaviors and properties in detail. Monoatomic refers to gases whose atoms are not bound to each other, such as noble gases like helium and argon.

Ideal gases are characterized by several simplifying assumptions: the volume of the gas particles themselves is negligible compared to the total volume of the gas, the particles are in constant, random motion and there are no intermolecular forces acting between them except during elastic collisions.

When dealing with problems regarding ideal monoatomic gases, like the reversible adiabatic expansion in our exercise, the simplicity of these assumptions allows us to effectively apply the ideal gas law and concepts such as the heat capacity ratio. Understanding these properties and how they impact equations and laws is foundational for accurately solving problems in physical chemistry related to gas behaviors.

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Most popular questions from this chapter

The equation of state for one mole of a gas is \(P V=R T+B P\), where \(B\) is a constant, independent of temperature. The internal energy of fixed amount of gas is function of temperature only. If one mole of the above gas is isothermally expanded from \(12 \mathrm{~L}\) to \(22 \mathrm{~L}\) at a constant external pressure of 1 bar at \(400 \mathrm{~K}\), then the change in enthalpy of the gas is approximately \((\mathrm{B}=2 \mathrm{~L} / \mathrm{mol})\) (a) 0 (b) \(-3.32 \mathrm{~J}\) (c) \(-332 \mathrm{~J}\) (d) \(-166 \mathrm{~J}\)

A definite mass of a monoatomic ideal gas at 1 bar and \(27^{\circ} \mathrm{C}\) expands against \(\begin{array}{llll}\text { vacuum } & \text { from } & 1.2 \mathrm{dm}^{3} & \text { to } & 2.4 \mathrm{dm}^{3} \text { . }\end{array}\) The change in free energy of the gas, \(\Delta G\), is \((R=0.08\) bar- \(\mathrm{L} / \mathrm{K}-\mathrm{mol}, \ln 2=0.7)\) (a) 0 (b) \(-64\) bar- 1 (c) \(+84 \mathrm{~J}\) (d) \(-84 \mathrm{~J}\)

A portion of helium gas in a vertical cylindrical container is in thermodynamic equilibrium with the surroundings. The gas is confined by a movable heavy piston. The piston is slowly elevated by a distance \(H\) from its equilibrium position and then kept in the elevated position long enough for the thermodynamic equilibrium to be re-established. After that, the container is insulated and then the piston is released. After the piston comes to rest, what is the new equilibrium position of the piston with respect to initial position? (a) The piston ends up \(0.4 H\) above its initial position (b) The piston ends up \(0.6 H\) above its initial position (c) The piston ends at its initial position (d) The piston ends up \(0.4 H\) below its initial position

Which of the following statement is correct? (a) Heat is thermodynamic property of system. (b) Work is thermodynamic property of system. (c) Work done by a conservative force is path function. (d) Heat involved in chemical reaction is path independent physical quantity.

An insulated container of gas has two chambers separated by an insulating partition. One of the chambers has volume \(V_{1}\) and contains an ideal gas at pressure \(P_{1}\) and temperature \(T_{1}\). The other chamber has volume \(V_{2}\) and contains the same ideal gas at pressure \(P_{2}\) and temperature \(T_{2}\). If the partition is removed without doing any work on the gas, the final equilibrium temperature of the gas in the container will be (a) \(\frac{T_{1} T_{2}\left(P_{1} V_{1}+P_{2} V_{2}\right)}{P_{1} V_{1} T_{2}+P_{2} V_{2} T_{1}}\) (b) \(\frac{P_{1} V_{1} T_{1}+P_{2} V_{2} T_{2}}{P_{1} V_{1}+P_{2} V_{2}}\) (c) \(\frac{P_{1} V_{1} T_{2}+P_{2} V_{2} T_{1}}{P_{1} V_{1}+P_{2} V_{2}}\) (d) \(\frac{T_{1} T_{2}\left(P_{1} V_{1}+P_{2} V_{2}\right)}{P_{1} V_{1} T_{1}+P_{2} V_{2} T_{2}}\)

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