Chapter 9: Problem 193
Given the data at \(25^{\circ} \mathrm{C}\) \(\mathrm{Ag}+\mathrm{I}^{-} \longrightarrow \mathrm{AgI}+\mathrm{e}^{-} ; E^{\circ}=0.152 \mathrm{~V}\) \(\mathrm{Ag} \longrightarrow \mathrm{Ag}^{+}+\mathrm{e}^{-} ; E^{\circ}=-0.800 \mathrm{~V}\) What is the value of \(\log \mathrm{K}_{\text {sp }}\) for \(\mathrm{AgI}\) ? \((2.303 \mathrm{RT} / F=0.059 \mathrm{~V})\) (a) \(-8.12\) (b) \(+8.612\) (c) \(-37.83\) (d) \(-16.13\)
Short Answer
Step by step solution
Understand the Reactions
Combine the Half-Reactions
Apply the Nernst Equation
Solve for \( \log K_{sp} \)
Finalize the Answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Standard Electrode Potential
In this context, the given half-reactions have their own \(E^{\circ}\) values: +0.152 V for Ag reacting with I- to form AgI and -0.800 V for Ag transforming into Ag+. The positive value indicates a favorable process for the formation of AgI, while the negative value shows the non-spontaneous dissociation of Ag into Ag+.
Understanding these values helps predict the direction of electron flow between the species involved in an electrochemical cell.
- A positive \(E^{\circ}\) suggests a stronger tendency for the reduction (gain of electrons).
- A negative \(E^{\circ}\) indicates a tendency for the oxidation process (loss of electrons).
Nernst Equation
In simpler terms, this equation connects the equilibrium condition of a redox reaction with its reaction quotient, essentially relating changes in concentration to changes in voltage.
The equation is expressed as:
\[E = E^{\circ} - \frac{2.303\,RT}{nF} \log Q\]
Where:
- \(E\) is the cell potential under non-standard conditions.
- \(E^{\circ}\) is the standard cell potential.
- \(R\) is the universal gas constant, \(8.314 \text{ J mol}^{-1} \text{K}^{-1}\).
- \(T\) is the temperature in Kelvin.
- \(n\) is the number of moles of electrons transferred in the reaction.
- \(F\) is Faraday’s constant, about \(96485 \text{ C mol}^{-1}\).
- \(Q\) is the reaction quotient, the ratio of concentrations of products to reactants.
Solubility Product Constant (Ksp)
\[\text{AgI} \rightleftharpoons \text{Ag}^+ + \text{I}^-\]
In this expression, \(K_{sp}\) is calculated as:
\[K_{sp} = [\text{Ag}^+][\text{I}^-]\]
Where the brackets denote the molar concentration of the ions in solution at equilibrium.
The exercise aims to find \(\log K_{sp}\), which is effectively \(\log_{10}\) of the solubility product constant. The sign and value of \(\log K_{sp}\) provide insightful understanding:
- Negative values imply low solubility, significant for predicting if a precipitant will form.
- A more negative \(\log K_{sp}\) indicates an extremely low concentration of dissolved ions for very insoluble compounds.