Chapter 8: Problem 190
When \(0.1\) mol of \(\mathrm{CH}_{3} \mathrm{NH}_{2}\left(\mathrm{~K}_{b}=5 \times 10^{-4}\right)\) is mixedwith \(0.08\) mol of \(\mathrm{HCl}\) and diluted to \(1 \mathrm{~L}\), the \(\mathrm{H}^{+}\)ion concentration in the solution is (a) \(8 \times 10^{-11} \mathrm{M}\) (b) \(6 \times 10^{-5} \mathrm{M}\) (c) \(1.6 \times 10^{-11} \mathrm{M}\) (d) \(8 \times 10^{-2} \mathrm{M}\)
Short Answer
Step by step solution
Understanding the System
Calculate Neutralization Reaction
Identify Resulting Buffer System
Calculate pK_a and pH of the Buffer
Calculate H^+ Concentration
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Henderson–Hasselbalch equation
- an acidic component (\[ \text{HA} \])
- and a basic component (\[ \text{A}^- \]).
- Balance between the conjugate acid–base pair, this is essential.
- The ratio informs whether the solution is more acidic or basic.
Acid-base reaction
- Molecules transferring protons from the acid (\( \text{HCl} \)) to the base (\( \text{CH}_3\text{NH}_2 \)), forming a new substance (\( \text{CH}_3\text{NH}_3^+ \)).
- The presence of chloride ions (\( \text{Cl}^- \)), which results from HCl dissociation.
pH calculation
- 20which is calculated by reversing the logarithmic operation, using: \[\text{H}^+ = 10^{-\text{pH}}\]
- Resulting in \( \text{H}^+ \) concentration.