Chapter 6: Problem 57
The enthalpy and entropy change for the reaction \(\mathrm{Br}_{2}(\mathrm{l})+\mathrm{Cl}_{2}(\mathrm{~g}) \longrightarrow 2 \mathrm{BrCl}(\mathrm{g})\) are \(30 \mathrm{~kJ} \mathrm{~mol}^{-1}\) and \(105 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\) respectively. The temperature at which the reaction will be in equilibrium is (a) \(450 \mathrm{~K}\) (b) \(300 \mathrm{~K}\) (c) \(285.7 \mathrm{~K}\) (d) \(273 \mathrm{~K}\)
Short Answer
Step by step solution
Understand the Problem
Use the Gibbs Free Energy Equation
Substitute Given Values
Calculate the Temperature
Choose the Closest Answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Enthalpy Change
- A positive \( \Delta H \) means the reaction absorbs heat (endothermic).
- A negative \( \Delta H \) signifies that the reaction releases heat (exothermic).