Chapter 6: Problem 17
For a reaction to occur spontaneously (a) \((\Delta \mathrm{H}-\mathrm{T} \Delta \mathrm{S})\) must be negative (b) \((\Delta \mathrm{H}+\mathrm{T} \Delta \mathrm{S})\) must be negative (c) \(\Delta \mathrm{H}\) must be negative (d) \(\Delta \mathrm{S}\) must be negative
Short Answer
Expert verified
(a) \((\Delta \mathrm{H}-\mathrm{T} \Delta \mathrm{S})\) must be negative.
Step by step solution
01
Understand Gibbs Free Energy
A reaction is spontaneous when the change in Gibbs free energy (\( \Delta G \)) is negative. The equation relating Gibbs free energy, enthalpy (\( \Delta H \)), and entropy (\( \Delta S \)) is \( \Delta G = \Delta H - T \Delta S \), where \( T \) is the temperature in Kelvin.
02
Analyze Option (a)
For (a), if \( (\Delta \mathrm{H}-\mathrm{T} \Delta \mathrm{S}) \) is negative, it directly implies that \( \Delta G \) is negative because \( \Delta G = \Delta \mathrm{H} - \mathrm{T} \Delta \mathrm{S} \). This means the process is spontaneous.
03
Analyze Option (b)
For (b), \( (\Delta \mathrm{H}+\mathrm{T} \Delta \mathrm{S}) \) would mean redefining Gibbs free energy. However, the concept doesn't align with the known condition for spontaneity (negative \( \Delta G \)), so this condition can't be correct.
04
Analyze Option (c)
For (c), having \( \Delta H \) negative characterizes an exothermic reaction, which may not be sufficient on its own for spontaneity without considering entropy \( \Delta S \).
05
Analyze Option (d)
For (d), if \( \Delta S \) is negative, this implies a decrease in entropy. A negative entropy alone, especially when combining it with enthalpy, doesn't necessarily guarantee \( \Delta G \) will be negative.
06
Identify the Correct Condition
The only option directly describing a necessary condition for spontaneity is (a), because \( (\Delta \mathrm{H}-\mathrm{T} \Delta \mathrm{S}) \) is equivalent to \( \Delta G \), and for a reaction to be spontaneous, \( \Delta G \) must be negative.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Gibbs Free Energy
Gibbs free energy, often denoted as \( \Delta G \), is a crucial concept in predicting whether a chemical reaction will occur spontaneously. It's a thermodynamic potential that balances the energies in play during a reaction. The equation \( \Delta G = \Delta H - T \Delta S \) connects Gibbs free energy with enthalpy (\( \Delta H \)) and entropy (\( \Delta S \)), where \( T \) represents the temperature in Kelvin. A reaction is considered spontaneous when \( \Delta G \) is negative, implying that the free energy of the system decreases.
Here’s how it works:
Here’s how it works:
- \( \Delta G < 0 \): The process is spontaneous.
- \( \Delta G = 0 \): The system is in equilibrium.
- \( \Delta G > 0 \): The process is non-spontaneous.
Enthalpy
Enthalpy, symbolized by \( \Delta H \), refers to the total heat content of a system. It's a measure often used to understand energy changes during a chemical reaction. When we say \( \Delta H \) is negative, we imply that the reaction releases heat, making it exothermic. In the context of Gibbs free energy, the enthalpy component plays a substantial role:
- Negative \( \Delta H \): Typically indicates that energy is released, favoring spontaneity.
- Positive \( \Delta H \): Indicates that energy is absorbed, which might hinder spontaneity unless compensated by favorable entropy (\( \Delta S \)).
Entropy
Entropy, denoted as \( \Delta S \), is a measure of disorder or randomness in a system. A higher entropy implies greater disorder. For spontaneity in chemical reactions, entropy is an equally important factor as enthalpy. Here's what you need to know about entropy:
- Magnitude of \( \Delta S \): A positive \( \Delta S \) suggests increased disorder, favoring spontaneity.
- Negative \( \Delta S \): Indicates decreased disorder, which might oppose spontaneity unless the enthalpy change is largely favorable.