Chapter 34: Problem 101
Which one among the following pairs of ions can not be separated by \(\mathrm{H}_{2} \mathrm{~S}\) in dilute hydrochloric acid? (a) \(\mathrm{Bi}^{3+}, \mathrm{Sn}^{4+}\) (b) \(\mathrm{Al}^{3+}, \mathrm{Hg}^{2+}\) (c) \(\mathrm{Zn}^{2+}, \mathrm{Cu}^{2+}\) (d) \(\mathrm{Ni}^{2+}, \mathrm{Cu}^{2+}\)
Short Answer
Step by step solution
Understanding the Precipitation Process
Evaluating Ion Separations in Dilute HCl
Determine the Non-Separable Ion Pair
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Metal Ion Precipitation
Some ions, like copper (Cu\(^{2+}\)), bismuth (Bi\(^{3+}\)), or mercury (Hg\(^{2+}\)), readily form insoluble sulfides. This characteristic allows them to be separated from ions that don't precipitate as easily under similar conditions. The selective precipitation of sulfide ions plays a crucial role in analyzing complex mixtures of metals.
Hydrogen Sulfide Precipitation
Different metal ions require varying conditions to precipitate as sulfides. Metal ions such as Cu\(^{2+}\) and Bi\(^{3+}\) react readily with H\(_2\)S to form insoluble sulfides, while others, like Zn\(^{2+}\) and Ni\(^{2+}\), remain in solution. Understanding these reactions helps chemists identify and separate ions in mixed solutions.
Acidity Influence on Precipitation
In general, metal ions that form stable complexes with water or require a higher pH to precipitate will not do so in acidic conditions. For instance, in a dilute HCl solution, Cu\(^{2+}\) readily forms an insoluble sulfide with H\(_2\)S, while Ni\(^{2+}\) does not precipitate effectively. This allows chemists to manipulate acidity and achieve selective precipitation for separation and analysis.
Separation of Metal Ions
In practice, the separation process can involve several steps, each requiring precision in controlling conditions such as pH and reagent concentration. Metal ions like Bi\(^{3+}\) and Sn\(^{4+}\) can be efficiently separated because they form different sulfides easily. However, some pairs, such as Ni\(^{2+}\) and Cu\(^{2+}\), pose challenges due to their similar responses under given conditions.
Chemical Separations in Solution
Understanding the solubility principles and reactivity of ions assists in designing procedures to achieve successful separation. In the context of hydrogen sulfide, the ability of some ions to precipitate in dilute HCl while others do not is a quintessential example of using chemical separations strategically. These techniques form the backbone of many analytical methods in chemistry, enabling accurate identification of components within a solution.