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Chapter 31: Problem 75

Choose the correct relationship for \(\alpha\)-D-glucose (A) and \(\beta\)-D-glucose (B). (a) \(\mathrm{A}\) and \(\mathrm{B}\) are crystal modification (b) A and B are epimers (c) A is an aldose and \(\mathrm{B}\) is a ketose (d) A is a pyranose sugar and \(\mathrm{B}\) is a furanose sugar

Short Answer

Expert verified
The correct relationship is (b): A and B are epimers.

Step by step solution

01

Understanding the Structures

First, recognize that both \( \alpha \)-D-glucose and \( \beta \)-D-glucose are forms of D-glucose, a simple sugar. The difference between them is related to the orientation of the hydroxyl group on the anomeric carbon (the first carbon) in the ring structure.
02

Analyzing Alpha and Beta Glucose

In \( \alpha \)-D-glucose, the hydroxyl group on the anomeric carbon is trans (opposite) to the CH\(_2\)OH group at carbon 6, whereas in \( \beta \)-D-glucose, it is cis (on the same side) to the CH\(_2\)OH group. Therefore, they differ in orientation at one specific carbon.
03

Identifying the Correct Relationship

The difference in orientation at the anomeric carbon classifies \( \alpha \)-D-glucose and \( \beta \)-D-glucose as anomers, a specific type of epimers. In general, epimers differ in configuration at only one chiral center out of several present in the molecule.
04

Selecting the Appropriate Answer

Given the definition of epimers and the specific difference at the anomeric carbon, the relationship described by option (b) best fits \( \alpha \)-D-glucose and \( \beta \)-D-glucose. They are epimers, but more specifically, they are anomers, which are a subset of epimers.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

D-glucose
D-glucose is one of the most important simple sugars in biology. It's a type of monosaccharide, specifically an aldohexose, given that it contains six carbon atoms and an aldehyde group. Glucose is the primary source of energy for cells in the body. Understanding its structure is key to grasping how it functions in various metabolic pathways.
  • **Basic Structure:** Glucose can exist in multiple forms; the predominant one being the pyranose, where it forms a six-membered ring.
  • **Chirality:** Glucose is a chiral molecule with multiple stereocenters. This means it can exist in different isomeric forms depending on the arrangement of functional groups around these stereocenters.
  • **Importance in Biology:** Besides being crucial for energy production, glucose also acts as a building block in several polysaccharides such as starch and cellulose.
Understanding these aspects of D-glucose helps us appreciate why it is so vital both structurally and functionally in living organisms.
Epimers
Epimers are a fascinating subset of stereoisomers. They refer to sugars that differ in configuration around just one specific carbon atom. It is essential to note that this difference can drastically change the properties of the sugar.
  • **Specificity:** Only one chiral center out of many in the molecule changes. This is what makes epimers unique compared to other stereoisomers, like enantiomers, which differ at every chiral center.
  • **Common Examples:** An example in carbohydrate chemistry is D-glucose and D-mannose, which are epimers differing at the C-2 position.
  • **Biological Significance:** The subtle change in a single carbon atom鈥檚 configuration can affect how a sugar interacts with enzymes and other molecules, which can alter biological pathways.
A thorough understanding of epimers allows scientists to manipulate carbohydrate chemistry effectively, especially in the synthesis of sugar analogues for therapeutic purposes.
Anomers
Anomers are a special type of epimers that are especially relevant in the chemistry of cyclic sugars. When a sugar cyclizes, forming a ring structure, a new chiral center is created at the former carbonyl carbon, now called the anomeric carbon.
  • **Anomeric Carbon:** This is the carbon where the linear form of a sugar forms a bond, creating either an  alpha (\( \alpha \)) or beta (\( \beta \)) configuration.
  • **Alpha and Beta Forms:** If the hydroxyl group attached to the anomeric carbon is on the opposite side (trans) of the CH\(_2\)OH group, it is labeled alpha (\( \alpha \)). If it is on the same side (cis), it is labeled beta (\( \beta \)).
  • **Significance in Nature:** The ability to interconvert between these forms, known as mutarotation, is an essential feature of sugars, allowing them to readily participate in biological reactions.
Anomers, because of their distinct orientation, can have diverse roles and functionalities in biological systems, which is why they hold an important place in carbohydrate chemistry.

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Most popular questions from this chapter

Hydrolysis of lactose with dilute acid yields (a) equimolar mixture of D-glucose and D-glucose (b) equimolar mixture of D-glucose and Dgalactose (c) equimolar mixture of D-glucose and D-fructose (d) equimolar mixture of D-galactose and Dgala-ctose

The number of monosaccharide molecules formed during hydrolysis from one mole of raffinose is

Which of the following statement(s) is/are correct? (a) The smallest aldose to form a cyclic hemi- acetal must have 4 carbon atoms. (b) D- glucose and D- fructose can be differentiated using Benedict's solution (c) When D- galactose is oxidised by \(\mathrm{HNO}_{3}\), it gives a meso isomer. (d) Aldoses react with Fehling's solution and \(\mathrm{PhNHNH}_{2}\) but not with \(\mathrm{NaHSO}_{3}\).

Consider the following statements about sucrose. 1\. hydrolysis of sucrose with dilute acid yields an equimolar mixture of D-glucose and D-fructose 2\. acid hydrolysis of sucrose is accompanied by a change in optical rotation 3\. in sucrose, the glycosidic linkage is between C-1 of glucose and \(\mathrm{C}-2\) of fructose 4\. aqueous solution of sucrose exhibits mutarotation Which of the statements are correct? (a) 1 and 2 only (b) 2 and 3 only (c) 1,2 and 3 (d) 1,3 and 4

Which of the following is true? (i) sucrose is a non reducing agent (ii) glucose is oxidized by bromine water (iii) glucose rotates plane polarized light in clockwise direction (iv) fructose is oxidized by bromine water Select the correct answer during the coded given below (a) (i), (ii), (iii) (b) (i), (ii) only (c) (ii), (iii) only (d) (i) (iv) only
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