/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 126 Consider the following haloalkan... [FREE SOLUTION] | 91影视

91影视

Consider the following haloalkanes: 1\. \(\mathrm{CH}_{3} \mathrm{~F}\) 2\. \(\mathrm{CH}_{3} \mathrm{Cl}\) 3\. \(\mathrm{CH}_{3} \mathrm{Br}\) 4\. \(\mathrm{CH}_{3} \mathrm{I}\) The increasing order of reactivity in nucleophilic substitution reaction is (a) \(4<3<2<1\) (b) \(1<3<2<4\) (c) \(1<2<3<4\) (d) \(1<2<4<3\)

Short Answer

Expert verified
(c) \(1<2<3<4\)

Step by step solution

01

Understanding Reactivity in Nucleophilic Substitution

The reactivity of haloalkanes in nucleophilic substitution reactions depends on the leaving group ability. A good leaving group is one that can depart as a relatively stable, weakly basic species.
02

Identifying Leaving Groups

The leaving groups in the given haloalkanes are F, Cl, Br, and I. The quality of a leaving group generally increases with the size of the halogen anion. Thus, in order of increasing leaving group ability, they are F < Cl < Br < I.
03

Applying to Haloalkanes

For the haloalkanes: 1. CH鈧僃 has fluorine as the leaving group. 2. CH鈧僀l has chlorine as the leaving group. 3. CH鈧傿r has bromine as the leaving group. 4. CH鈧僆 has iodine as the leaving group. Iodine is the best leaving group, making CH鈧僆 the most reactive in nucleophilic substitution. Conversely, fluorine is the poorest leaving group, making CH鈧僃 the least reactive.
04

Arranging in Increasing Order of Reactivity

The increasing order of reactivity in nucleophilic substitution based on the leaving group ability is: CH鈧僃 < CH鈧僀l < CH鈧傿r < CH鈧僆. This corresponds to the option (c) in the multiple-choice question.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Haloalkanes Reactivity
Haloalkanes, also known as alkyl halides, are compounds in which a halogen atom is bonded to an alkyl group. Their reactivity in nucleophilic substitution reactions varies significantly. In these reactions, a nucleophile replaces the halogen atom, known as the leaving group. These reactions are common and essential in organic chemistry, leading to the formation of new compounds.
The reactivity of haloalkanes largely depends on two main factors: the stability of the leaving group and the structure of the carbon chain to which it is attached. In our context, the ability of the leaving group plays a more pivotal role in determining reactivity. The larger the halogen atom, the more reactive the haloalkane tends to be. This is because larger halogen atoms form more stable anions when they leave the molecule, making the substitution process more favorable. For example, in our set of haloalkanes, CH鈧僃, CH鈧僀l, CH鈧傿r, and CH鈧僆, the reactivity increases with the size of the halogen: F < Cl < Br < I. Therefore, CH鈧僆 is the most reactive while CH鈧僃 is the least.
Leaving Group Ability
The concept of a leaving group is central to understanding nucleophilic substitution reactions. A leaving group is an atom or group of atoms that detaches from the parent molecule during the reaction. The effectiveness of a leaving group is determined by its ability to stabilize the negative charge after departure.
In general, a good leaving group is a weak base and a stable anion. This characteristic allows it to leave without causing the parent molecule to become overly unstable or reactive. As we analyze the halogens 鈥 fluoride, chloride, bromide, and iodide 鈥 iodide is observed to be the best leaving group. This is due to its larger size which enables it to disperse the negative charge over a larger volume, contributing to its stability. Consequently, when comparing haloalkanes, those with better leaving groups (like iodine in CH鈧僆) will undergo nucleophilic substitution more readily compared to those with poorer leaving groups (like fluorine in CH鈧僃). Understanding this allows chemists to predict reaction speeds and choose suitable conditions for desired chemical processes.
Halogen Anions
Halogen anions are the negatively charged ions formed when halogens gain an electron. They play a crucial role in determining the leaving group ability of halogenated compounds. Each halogen has a distinct anionic form: fluoride (F鈦), chloride (Cl鈦), bromide (Br鈦), and iodide (I鈦).
Let's delve into their characteristics. **Fluoride (F鈦)**, due to its small size, holds its negative charge tightly, making it a poor leaving group. **Chloride (Cl鈦)** is slightly larger and, therefore, a somewhat better leaving group. **Bromide (Br鈦)**, being larger still, is even more suitable. Finally, **iodide (I鈦)** is the largest and most stable due to its ability to effectively diffuse the negative charge, making it the best leaving group among the halogens.

This hierarchy of leaving group quality directly translates into the order of reactivity for haloalkanes in nucleophilic substitution: **CH鈧僃 < CH鈧僀l < CH鈧傿r < CH鈧僆**. As such, knowledge of halogen anions not only aids in understanding their reactive nature but also plays a decisive role in predicting and controlling organic reactions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.