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The correct IUPAC name of \(\mathrm{KAl}\left(\mathrm{SO}_{4}\right)_{2} .12 \mathrm{H}_{2} \mathrm{O}\) is (a) aluminium potassium sulphate-12-water (b) potassium aluminium(III) sulphate-12-water (c) potassium aluminium(III) sulphate hydrate (d) aluminium(III) potassium sulphate hydrate-12

Short Answer

Expert verified
The correct IUPAC name is (b) potassium aluminium(III) sulphate-12-water.

Step by step solution

01

Analyze the Chemical Formula

The compound given is KAl(SO鈧)鈧 路 12H鈧侽, which is a type of ionic compound known as an alum. Essentially, it consists of a double salt with potassium (K), aluminium (Al), and sulfate (SO鈧). Also, the 12 molecules of water indicate it is a hydrated compound.
02

Assign Oxidation States and Identify the Cations

Potassium (K) has an oxidation state of +1. Aluminium is here in the form of Al鲁鈦 indicating an oxidation state of +3. Thus, the name must reflect the oxidation state of the aluminium which is +3.
03

Understand Sulphate Group Contribution

Each sulphate group (SO鈧劼测伝) contributes a -2 charge. The compound has two sulphate ions in the formula balancing the charge of 2 Al鲁鈦 and 1 K鈦 ions, confirming the composition suits Al in the +3 state.
04

Recognize the Role of Water

The '路 12H鈧侽' part of the formula indicates there are 12 water molecules of hydration, which needs to be reflected in the name. This is a key factor as it specifies the hydration state of the compound.
05

Determine the Correct IUPAC Name

Considering all components: the main metal cation (potassium), the secondary metal with oxidation state (aluminium(III)), the anion (sulphate), and the water of crystallization (12-water), the correct IUPAC name is developed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oxidation States
Understanding oxidation states is key to determining the proper name of compounds. An oxidation state indicates the degree of oxidation (loss of electrons) of an element in a compound. Each element can have multiple oxidation states, representing different ion charges in chemical reactions.
In KAl(SO鈧)鈧 路 12H鈧侽, we find potassium (K) and aluminium (Al) exhibiting distinct oxidation states. Potassium is a metal that typically has a +1 oxidation state, meaning it loses one electron to form a positively charged ion (K鈦).
Aluminium in this compound is in the +3 oxidation state, represented as Al鲁鈦. This means aluminium gives up three electrons, which is indicated in its name as aluminium(III). Recognizing these states helps us in understanding how elements combine and form stable compounds.
Hydration in Compounds
Hydrated compounds incorporate water into their crystalline structure. The formula KAl(SO鈧)鈧 路 12H鈧侽 tells us that 12 water molecules are associated with each formula unit of the compound.
This word 'hydrate' refers specifically to the presence of these water molecules. The water in the compound is not just trapped but integrated structurally. Often, these water molecules are crucial for the stability or properties of the compound, affecting characteristics like solubility.
When naming such compounds, we represent this feature in its name. For example, in the compound discussed, this is denoted by phrases like '12-water' or 'dodecahydrate' in the IUPAC nomenclature.
Ionic Compounds
Ionic compounds consist of cations and anions held together by ionic bonds. These ions are formed when metals lose electrons (to form cations) and non-metals gain electrons (to form anions).
In the case of KAl(SO鈧)鈧 路 12H鈧侽, we see potassium (K鈦) and aluminium (Al鲁鈦) as the cations. The sulphate ion (SO鈧劼测伝) acts as the stable anion balancing the overall charge of the compound.
This type of compound generally forms a solid crystal lattice, making them distinct in terms of physical properties. These features, including charge balance, are reflected in how the compound is named and understood through IUPAC nomenclature.
Double Salts
Double salts are ionic compounds comprising two different metal cations. They differ from simple salts due to this complexity in their structure.
The compound KAl(SO鈧)鈧 路 12H鈧侽 is a double salt because it contains two types of metal cations, potassium (K) and aluminium (Al).
Double salts like this are interesting because they exhibit properties that are distinct and sometimes enhanced when compared to their constituent simple salts. Their behavior often changes when dissolved in water, where they dissociate into their individual ions, exhibiting unique chemical properties distinct from single salts.

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Most popular questions from this chapter

When degenerate d-orbitals of an isolated atom/ion are brought under the impact of magnetic field of ligands, the degeneracy is lost. The two newly formed sets of d-orbitals, depending upon nature and magnetic field of ligands are either stabilized or destabilized. The energy difference between the two sets whenever lies in the visible region of the electromagnetic spectrum, then the electronic transition \(\mathrm{t}_{2 \mathrm{~g}} \rightleftharpoons \mathrm{e}_{\mathrm{g}}\) are responsible for colours of the co-ordination compounds Which of following complex ions will be coloured in aqueous state? (a) \(\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}\) (b) \(\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\) (c) \(\left[\mathrm{Sc}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\) (d) Both (b) and (c)

The main draw back of valence bond theory is/are (a) It cannot explain magnetic properties of co-ordination compounds (b) It cannot distinguish between high spin and low spin complex (c) It does not provide an answer to the origin of characteristic colours of complex ions (d) It is a qualitative approach

Which of the following pairs represents linkage isomers? (a) \(\left[\mathrm{Pd}\left(\mathrm{P} \mathrm{Ph}_{3}\right)_{2}(\mathrm{NCS})_{2}\right]\) and \(\left[\mathrm{Pd}\left(\mathrm{P} \mathrm{Ph}_{3}\right)_{2}(\mathrm{SCN})_{2}\right]\) (b) \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{NO}_{3}\right] \mathrm{SO}_{4}\) and \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{SO}_{4}\right] \mathrm{NO}_{3}\) (c) \(\left[\mathrm{Pt} \mathrm{Cl}_{2}\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{Br}_{2}\) and (d) \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]\left[\mathrm{Pt} \mathrm{Cl}_{4}\right]\) and \(\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{4}\right]\left[\mathrm{CuCl}_{4}\right]\)

Nickel \((\mathrm{Z}=28)\) combines with a uninegative monodentate ligand \(\mathrm{X}\) - to form a paramagnetic complex \(\left[\mathrm{NiX}_{4}\right]^{2}\), the number of unpaired electrons in nickel and the geometry of this complex ion is (a) one, tetrahedral (b) two, tetrahedral (c) one, square planar (d) two, square planar

Consider the following spatial arrangements of the octahedral complex ion \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}\right]^{+} .\) Which of the following statements is incorrect regarding these structures? (a) 2 and 3 are cis and trans isomers respectively (b) 1 and 3 are enantiomers (c) 3 and 4 have identical structures (d) 2 and 4 are trans and cis isomers respectively

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