Chapter 20: Problem 117
Which of the following are diamagnetic? (a) \(\left[\mathrm{Ni}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\) (b) \(\left[\mathrm{Zn}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}\) (c) \(\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}\) (d) \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}\)
Short Answer
Step by step solution
Determine the electronic configuration
Identify ligand field strength
Determine spin state and magnetic property
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ligand Field Theory
- Strong field ligands like CN- cause a large splitting of the d-orbitals. This typically results in low-spin complex formations, where electrons pair up in lower energy orbitals before occupying higher levels.
- Weak field ligands such as H2O and NH3 result in smaller splitting. This means more unpaired electrons and often leads to high-spin complexes, where electrons are spread across both low and high energy orbitals to minimize repulsion.
Magnetic Properties
- Diamagnetic substances have all paired electrons. In these complexes, the magnetic effects cancel out, causing them to be generally repelled by magnetic fields. An example is \(\left[\mathrm{Zn(NH_3)_4}\right]^{2+}\), which is diamagnetic due to its fully paired d-orbital electrons.
- Paramagnetic substances contain unpaired electrons, leading to a net magnetic moment. Such complexes are attracted to magnetic fields. High-spin complexes, where ligands are weak field, are often paramagnetic, much like \(\left[\mathrm{Co(NH_3)_6}\right]^{3+}\).
Electronic Configuration of Transition Metals
- Ni2+: Often \([ ext{Ar}] 3d^8 4s^0\). This configuration helps predict whether a nickel complex, such as \(\left[\mathrm{Ni(CN)_4}\right]^{2-}\), will be diamagnetic due to the strong field effect of CN-.
- Zn2+: Configured as \([ ext{Ar}] 3d^{10} 4s^0\), making all electrons paired and leading to a diamagnetic nature in \(\left[\mathrm{Zn(NH_3)_4}\right]^{2+}\).