Chapter 18: Problem 63
The solubility of \(\mathrm{AgBr}\) in hypo is due to the formation of (a) \(\mathrm{Ag}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}\) (b) \(\left[\operatorname{Ag}\left(\mathrm{S}_{2} \mathrm{O}_{3}\right)\right]^{-}\) (c) \(\left[\mathrm{Ag}\left(\mathrm{S}_{2} \mathrm{O}_{3}\right)_{2}\right]^{3-}\) (d) \(\mathrm{Ag}_{2} \mathrm{SO}_{3}\)
Short Answer
Step by step solution
Identify the Dissociation Products
Examine the Possible Complexes
Determine the Correct Complex
Select the Correct Answer
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Silver bromide
Complex ion formation
Thiosulfate complex
Solubility enhancement
- In photography, this solubility enhancement helps in the developing process by ensuring all silver halides are removed from negatives, leaving behind only the desired image.
- In chemistry, enhanced solubility allows for reactions to proceed more efficiently by maintaining a higher concentration of the reactive species in solution.
- Environmentally, it aids in the treatment of silver waste, reducing solid waste and enabling the recycling of silver from solutions.