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The electronegativity difference between \(\mathrm{N}\) and \(\mathrm{F}\) is greater than that between \(\mathrm{N}\) and \(\mathrm{H}\), yet the dipole moment of \(\mathrm{NH}_{3}(1.5 \mathrm{D})\) is larger than that of \(\mathrm{NF}_{3}\) \((0.2 \mathrm{D})\) This is because (a) in \(\mathrm{NH}_{3}\) as well as \(\mathrm{NF}_{3}\) the atomic dipole and bond dipole are in opposite directions (b) in \(\mathrm{NH}_{3}\) the atomic dipole and bond dipole are in the opposite directions whereas in \(\mathrm{NF}_{3}\) these are in the same direction (c) in \(\mathrm{NH}_{3}\) as well as in \(\mathrm{NF}_{3}\) the atomic dipole and bond dipole are in same direction (d) in \(\mathrm{NH}_{3}\) the atomic dipole and bond dipole and in the same direction whereas in \(\mathrm{NF}_{3}\) these are in opposite directions

Short Answer

Expert verified
Option (d) is correct: In NH₃, the dipoles are aligned; in NF₃, they are opposite.

Step by step solution

01

Understand the Concept of Dipole Moment

The dipole moment is a measure of the separation of positive and negative charge in a molecule, affecting its polar nature. It depends on both the individual atomic dipoles and the overall molecular geometry.
02

Compare Electronegativity Differences

The electronegativity difference affects the bond dipole. Nitrogen (N) versus Fluorine (F) has a greater electronegativity difference compared to Nitrogen (N) versus Hydrogen (H). This suggests stronger bond dipoles toward F than H.
03

Analysis of Molecular Shape

NH₃ and NF₃ both have a trigonal pyramidal shape due to the lone pair on nitrogen. However, the direction of bond dipoles and the lone pair causes different net dipole moments.
04

Direction of the Bond and Molecular Dipoles

For NH₃, the bond dipoles are directed towards nitrogen, and the lone pair also contributes in the same direction, leading to a strong net dipole moment. For NF₃, the highly electronegative fluorines direct the bond dipoles away from nitrogen, but the lone pair is not aligned to add to the net dipole effectively.
05

Conclusion and Selection of Correct Option

In NH₃, the atomic dipole due to the lone pair and the bond dipoles are aligned, increasing the dipole moment. In NF₃, the lone pair's dipole partially cancels out the dipoles from the N-F bonds. Therefore, option (d) is correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electronegativity
Electronegativity is a chemical property that describes how strongly an atom can attract electrons towards itself in a chemical bond. It plays a crucial role in determining the bond's polarity within a molecule.
Fluorine is known to be the most electronegative element. When it bonds with nitrogen, the bond is highly polar due to the significant electronegativity difference. Meanwhile, nitrogen is also more electronegative than hydrogen, but the difference is smaller.
This variance affects the bond dipoles, which are the individual dipole moments of each bond within a molecule. The larger the electronegativity difference, the more polarized the bond will be, meaning a stronger bond dipole.
This concept is pivotal when comparing molecules like NH₃ and NF₃. Despite NF₃ having a greater electronegativity difference and potentially stronger bond dipoles, the overall molecular dipole moment is influenced by other factors such as molecular geometry.
Molecular Geometry
Molecular geometry refers to the three-dimensional arrangement of atoms in a molecule, impacting its physical and chemical properties, including dipole moment.
Both NH₃ and NF₃ have a trigonal pyramidal geometry. This shape is due to the presence of a lone pair of electrons on the nitrogen atom, which exerts a repulsive force pushing the bonds into this particular formation.
Despite having the same geometry, the orientation of dipoles in these molecules differs. In NH₃, the lone pair and bond dipoles align to enhance the net dipole moment. In contrast, in NF₃, the orientation of bond dipoles is such that the influence of the lone pair is diminished, leading to a lower net dipole moment.
Understanding molecular geometry helps predict how bond dipoles might cancel out or add up, affecting the overall molecular dipole moment.
Bond Dipole
A bond dipole occurs when there is a difference in electronegativity between two atoms in a bond, causing a displacement of electron density from one atom to another.
The direction of a bond dipole is from the less electronegative element towards the more electronegative element. In NH₃, the N-H bonds have dipoles directed towards nitrogen. In NF₃, the N-F bonds have dipoles directed towards fluorine.
However, the overall dipole moment of a molecule is not just a sum of bond dipoles. It also depends greatly on the spatial arrangement of these dipoles and any lone pairs. For instance, in NH₃, bond dipoles and the dipole due to the lone pair are in the same direction, leading to a greater net dipole moment. In NF₃, they are in opposing directions, which reduces the net dipole moment.
By understanding bond dipoles within the context of molecular structure, one can deduce the polarity and subsequent behavior of molecules in varied environments.

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Most popular questions from this chapter

When anions and cations approach each other, the valence shell of anions are pulled towards cation nucleus and thus, shape of anion is deformed. The phenomenon of deformation of anion by a cation is known as polarization and the ability of the cation to polarize the anion is called as polarizing power of cation. Due to polarization, sharing of electrons occurs between two ions to some extent and the bond shows some covalent character. Considering \(\mathrm{BeCl}_{2}, \mathrm{MgCl}_{2}, \mathrm{CaCl}_{2}\) and \(\mathrm{BaCl}_{2}\), predict which of the following statement is true? (a) Covalent character increases as the atomic number of the metal atom increases (b) \(\mathrm{BeCl}_{2}\) is least ionic out of the given chlorides. (c) \(\mathrm{BeCl}_{2}\) has the highest melting point among the given chlorides. (d) All are highly ionic compound.

Bond order of nitric oxide is (a) 1 (b) \(2.5\) (c) 2 (d) \(1.5\)

Among the following compounds which contain all 3 type of bonds (i) \(\mathrm{NH}_{4} \mathrm{Cl}\) (ii) \(\mathrm{K}_{3} \mathrm{Fe}(\mathrm{CN})_{6}\) (iii) \(\mathrm{H}_{2} \mathrm{O}_{2}\) (iv) \(\mathrm{H}_{2} \mathrm{SO}_{4}\) (v) \(\mathrm{CaCO}_{3}\) (a) I, II (b) I, II, V (c) I, II, IV (d) I, II, III

When one of the following molecules is expected to exhibit diamagnetic behaviour? (a) \(\mathrm{O}_{2}\) (b) \(\mathrm{S}_{2}\) (c) \(\mathrm{C}_{2}\) (d) \(\mathrm{N}_{2}\)

The common features among the species \(\mathrm{CN}^{-}, \mathrm{CO}\) and \(\mathrm{NO}^{+}\)are (a) bond order three and isoelectronic (b) bond order three and weak field ligands (c) bond order two and \(\pi\)-acceptors (d) isoelectronic and weak field ligands.

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