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Match the following: \(\begin{array}{ll}\text { List I } & \text { List II }\end{array}\) (Species) (Hybridization) 1\. \(\mathrm{BCI}_{3}\) (i) \(\mathrm{sp}^{3}\) 2\. \(\mathrm{NH}_{3}\) (ii) \(\mathrm{sp}^{3} \mathrm{~d}^{2}\) 3\. \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}\) (iii) \(\mathrm{sp}^{2}\) 4\. \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\) (iv) \(\mathrm{sp}^{2} \mathrm{~d}\)

Short Answer

Expert verified
1-iii, 2-i, 3-iv, 4-ii

Step by step solution

01

Determine Hybridization of BCI3 (Species 1)

The molecule \( \text{BCI}_3 \) is trigonal planar in shape. This geometry corresponds to \( \text{sp}^2 \) hybridization as it involves the mixing of one \( s \) orbital and two \( p \) orbitals to form three equivalent sp2 hybrid orbitals. Therefore, \( \text{BCI}_3 \) matches with \( (iii) \ \text{sp}^2 \) hybridization.
02

Determine Hybridization of NH3 (Species 2)

The molecule \( \text{NH}_3 \) is pyramidal in shape with nitrogen forming three single bonds and one lone pair. This corresponds to an \( \text{sp}^3 \) hybridization, involving one \( s \) orbital and three \( p \) orbitals. Thus, \( \text{NH}_3 \) matches with \( (i) \ \text{sp}^3 \) hybridization.
03

Determine Hybridization of [Cu(NH3)4]2+ (Species 3)

In the complex \( [\text{Cu(NH}_3)_4]^{2+} \), copper typically forms a square planar geometry in this complex, leading to \( \text{sp}^2 \text{d} \) hybridization, though often discussed in terms of \( \text{dsp}^2 \) due to involvement of d orbitals. But here it's primarily the concept of \( \text{sp}^2 \text{d} \) involved in creating a planar shape, matching \( (iv) \ \text{sp}^2 \text{d} \) hybridization.
04

Determine Hybridization of [Fe(H2O)6]2+ (Species 4)

The complex \( [\text{Fe(H}_2\text{O})_6]^{2+} \) typically exhibits an octahedral geometry, which corresponds to \( \text{sp}^3\text{d}^2 \) hybridization. This involves mixing one \( s \), three \( p \), and two \( d \) orbitals. Hence, it matches with \( (ii) \ \text{sp}^3\text{d}^2 \) hybridization.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonal Planar
Trigonal planar geometry is observed in molecules where a central atom is bonded to three surrounding atoms. These atoms are evenly distributed around the central atom, creating a flat, triangular shape. The bond angles in a trigonal planar molecule are typically 120 degrees. This arrangement occurs due to the sp虏 hybridization of the central atom's orbitals.

Key features of trigonal planar molecules include:
  • Flat, triangular geometry.
  • Bond angles of approximately 120 degrees.
  • Three atoms bonded to a central atom.
In the molecule boron trichloride (BCI鈧), boron is the central atom, bonded to three chlorine atoms. The boron in BCI鈧 undergoes sp虏 hybridization, using its s and two of its p orbitals to form three equivalent hybrid orbitals. This results in the trigonal planar shape, where the three chlorines are positioned symmetrically around boron.
Pyramidal Shape
A pyramidal shape is commonly seen in molecules with a central atom bonded to three other atoms and having one lone pair. This shape is distinct from the trigonal planar because of the lone pair which pushes the bonded atoms downwards, altering the geometric arrangement.

The nitrogen atom in ammonia (NH鈧) is a classic example demonstrating sp鲁 hybridization. Here's what you need to know:
  • Four hybrid orbitals are formed from one s and three p orbitals.
  • Three of these orbitals form bonds with hydrogen atoms.
  • The fourth orbital holds the lone pair.
The presence of the lone pair distorts the bond angles from the ideal tetrahedral angle of 109.5 degrees to about 107 degrees, forming a pyramidal shape rather than a planar one.
Square Planar
Square planar geometry is prominent in certain coordination complexes, where four ligands are arranged at the corners of a square around a central atom. This geometry is most often associated with transition metals.

In the complex ion \([ ext{Cu(NH}_3)_4]^{2+} \), copper exhibits a square planar geometry, a result of sp虏d hybridization, sometimes alternatively described as dsp虏 hybridization due to the involvement of d orbitals. interesting characteristics include:
  • Four ligands positioned at 90-degree angles, creating a square.
  • Characteristics usually appear in complexes with d鈦 metal ions.
This geometry is particularly stable due to the minimization of electron repulsion between ligands, setting it apart from other potential shapes.
Octahedral Geometry
The octahedral geometry is characteristic of species where six ligands surround a central atom, positioned symmetrically at the corners of an octahedron. It is a common geometry for transition metal complexes, resulting from the mixing of one s, three p, and two d orbitals leading to sp鲁d虏 hybridization.

Consider the complex ion \([ ext{Fe(H}_2 ext{O})_6]^{2+} \):
  • Iron in the center surrounded by six water molecules.
  • Exhibits sp鲁d虏 hybridization.
  • Creates equal bond angles of exactly 90 degrees between adjacent ligands.
The octahedral shape allows for optimal space filling and electron pair repulsion minimization, making it energetically favorable for many complexes.

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Most popular questions from this chapter

The charge/size ratio of a cation determines its polarizing power. Which one of the following sequences represents the increasing order of the polarizing power of the cationic species, \(\mathrm{K}^{+}, \mathrm{Ca}^{2+}, \mathrm{Mg}^{2+}, \mathrm{Be}^{2+}\) ? (a) \(\mathrm{Be}^{2+}<\mathrm{K}^{+}<\mathrm{Ca}^{2+}<\mathrm{Mg}^{2+}\) (b) \(\mathrm{K}^{+}<\mathrm{Ca}^{2+}<\mathrm{Mg}^{2+}<\mathrm{Be}^{2+}\) (c) \(\mathrm{Ca}^{2+}<\mathrm{Mg}^{2+}<\mathrm{Be}^{2+}<\mathrm{K}^{+}\) (d) \(\mathrm{Mg}^{2+}<\mathrm{Be}^{2+}<\mathrm{K}^{+}<\mathrm{Ca}^{2+}\)

\(\mathrm{H}_{2} \mathrm{O}\) is dipolar, whereas \(\mathrm{BeF}_{2}\) is not. It is because (a) the electronegativity of \(\mathrm{F}\) is greater than that of \(\mathrm{O}\) (b) \(\mathrm{H}_{2} \mathrm{O}\) involves hydrogen bonding where as \(\mathrm{BeF}_{2}\) is a discrete molecule (c) \(\mathrm{H}_{2} \mathrm{O}\) is linear and \(\mathrm{BeF}_{2}\) is angular (d) \(\mathrm{H}_{2} \mathrm{O}\) is angular and \(\mathrm{BeF}_{2}\) is linear

The molecules that will have dipole moment (1) 2,2 -dimethylpropane (2) trans-1-pent-2-ene (3) cis-hex-3-ene (4) \(2,2,3,3\)-tetramethylbutane (a) 2,3 (b) 1,3 (c) \(1,2,3\) (d) all of these

Arrange the following compounds in order of increasing dipole moment 1\. Toluene, 2\. m-dichlorobenzene 3\. o-dichlorobenzene, 4\. p-dichlorobenzene (a) \(1<4<2<3\) (b) \(4<1<2<3\) (c) \(4<1<3<2\) (d) \(4<2 \leq 1<3\)

In which of the following pairs of molecules/ions, both the species are not likely to exist? (a) \(\mathrm{H}_{2}^{2+}, \mathrm{He}_{2}\) (b) \(\mathrm{H}_{2}^{-}, \mathrm{H}_{2}^{2+}\) (c) \(\mathrm{H}_{2}^{+}, \mathrm{He}_{7}^{2-}\) (d) \(\mathrm{H}_{2}^{-}, \mathrm{He}_{2}^{2-}\)

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