Chapter 12: Problem 151
The lanthanide contraction is responsible for the fact that \([\mathbf{2 0 0 5}]\) (a) \(\mathrm{Zr}\), Hf have about the same radius (b) \(\mathrm{Zr}, \mathrm{Y}\) have about the same radius (c) \(\mathrm{Zr}\), Nb have same oxidation state (d) \(\mathrm{Zr}, \mathrm{Zn}\) have same oxidation state
Short Answer
Step by step solution
Understanding Lanthanide Contraction
Analyzing Atomic Radius Trends
Reviewing the Options
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Effective Nuclear Charge
Factors affecting effective nuclear charge include:
- Shielding Effect: Inner electrons repel outer electrons, reducing the effective charge felt by the outer electrons.
- Penetration: How certain orbitals allow electrons to experience the nucleus's charge more effectively than others.
Lanthanide Series
- Similar Chemical Properties: All lanthanides exhibit similar chemical behavior, largely due to the fact that they usually display the +3 oxidation state.
- Contraction: As electrons fill the 4f orbitals, the size of the atoms decreases steadily, which is not the usual trend across a series in the periodic table.
- Magnetic and Optical Properties: Many of these elements are used in electronics and optics due to their magnetic and luminescent characteristics.
Atomic Radius Trends
- Across a Period: Atomic radii generally decrease due to an increased effective nuclear charge, where additional protons pull the electron cloud closer to the nucleus.
- Down a Group: Atomic radii increase since new electron shells are added, making atoms larger and the effect of increased nuclear charge is somewhat offset by increased distance from the nucleus.
- Irregularities: Exceptions can occur, such as the lanthanide contraction, where added 4f electrons do not contribute to increased shielding, resulting in smaller atomic radii in later elements.