/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 175 Which one of these is not an aci... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 8: Problem 175

Which one of these is not an acid salt ? (a) \(\mathrm{NaH}_{2} \mathrm{PO}_{2}\) (b) \(\mathrm{NaH}_{2} \mathrm{PO}_{3}\) (c) \(\mathrm{Na}_{2} \mathrm{H}_{2} \mathrm{~S}_{2} \mathrm{O}_{7}\) (d) \(\mathrm{NaH}_{2} \mathrm{PO}_{4}\)

Short Answer

Expert verified
The compound \(\mathrm{NaH}_2 \mathrm{PO}_2\) is not an acid salt.

Step by step solution

01

Understanding Acid Salts

An acid salt is a salt containing hydrogen ions (H\(^+\)), which are replaceable when in solution. It typically forms when a polybasic acid is not completely neutralized.
02

Examining Option (a)

- Compound: \(\mathrm{NaH}_2 \mathrm{PO}_2\). - Hypophosphorous acid (H\(_3\)PO\(_2\)) forms \(\mathrm{NaH}_2\mathrm{PO}_2\) when partially neutralized. - Only has one replaceable H; forms only normal salt, not an acid salt.
03

Examining Option (b)

- Compound: \(\mathrm{NaH}_2 \mathrm{PO}_3\). - Formed from phosphorous acid (H\(_3\)PO\(_3\)) when not fully neutralized. - This compound has replaceable hydrogen ions, fitting the definition of an acid salt.
04

Examining Option (c)

- Compound: \(\mathrm{Na}_2 \mathrm{H}_2 \mathrm{~S}_2 \mathrm{O}_7\). - Pyrosulfuric acid (H\(_2\)S\(_2\)O\(_7\)) forms this compound when partially neutralized. - Contains replaceable hydrogen ions, making it an acid salt.
05

Examining Option (d)

- Compound: \(\mathrm{NaH}_2 \mathrm{PO}_4\). - Derived from phosphoric acid (H\(_3\)PO\(_4\)) and features replaceable hydrogen ions. - Also fits as an acid salt with replaceable hydrogen.
06

Final Conclusion

Upon reviewing all compounds, \(\mathrm{NaH}_2 \mathrm{PO}_2\) from option (a) does not behave as an acid salt since it does not have additional replaceable hydrogen ions.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polybasic Acid
A polybasic acid is a type of acid with more than one hydrogen atom that can be replaced by metal ions or other cations during a reaction. This makes polybasic acids distinct, as they can form various types of salts depending on the degree of neutralization. Examples of polybasic acids include:
  • Phosphoric Acid (H鈧働O鈧�): Contains three replaceable hydrogen ions.
  • Sulfuric Acid (H鈧係O鈧�): Contains two replaceable hydrogen ions.
When these acids are partially neutralized, they often form acid salts. For instance, when not all hydrogen ions are replaced, the remaining hydrogen can still participate in further reactions. Understanding the behavior of polybasic acids is central to grasping the concept of acid salts, as they provide multiple opportunities for forming new compounds during neutralization.
Replaceable Hydrogen Ion
The concept of replaceable hydrogen ions is central to understanding acids and acid salts. In an acid, a hydrogen ion (H鈦�) can be released in solution, often replacing by metal ions in the formation of a salt. Consider these key points:
  • Replaceable hydrogen ions determine the strength and properties of an acid.
  • The more replaceable hydrogen ions an acid has, the more complex the potential salts it can form.
For example, in phosphoric acid (H鈧働O鈧�), there are three replaceable hydrogen ions. This allows it to form various types of salts, including mono, di, and triprotic salts based on how many hydrogen ions are replaced. Identifying which hydrogen ions can be replaced helps in predicting the possible compounds resulting from partial or complete neutralization.
Partial Neutralization
Partial neutralization occurs when not all the replaceable hydrogen ions in an acid are replaced by metal ions, leading to the formation of an acid salt. This is a crucial step in the chemical reaction between acids and bases, allowing for the development of a variety of salts from a single polybasic acid. Key considerations in partial neutralization:
  • The process stops before all hydrogen ions are replaced.
  • It results in the formation of an intermediate salt 鈥� the acid salt 鈥� which retains some acidic property due to remaining hydrogen ions.
In practice, let's say phosphorous acid (H鈧働O鈧�) goes through partial neutralization. It can yield the acid salt NaH鈧侾O鈧� when two hydrogen ions are replaced. This leaves one hydrogen ion intact, enabling the compound to display characteristics of both an acid and a salt. Understanding this process helps clarify how various acid-base reactions yield specific, functional compounds.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The Ka value of formic acid and acetic acid are respectively \(1.77 \times 10^{-4}\) and \(1.75 \times 10^{-5}\). the ratio of the acid strength of \(0.1 \mathrm{~N}\) acids is (a) \(0.1\) (b) \(0.3\) (c) \(3.178\) (d) 100

When \(60 \mathrm{ml}\) of \(0.1 \mathrm{M} \mathrm{Ca}\left(\mathrm{NO}_{3}\right)_{2}\) is mixed with \(40 \mathrm{ml}\) of \(0.125 \mathrm{M} \mathrm{Na}_{2} \mathrm{CO}_{3}, \mathrm{CaCO}_{3}\) precipitates. If \(\mathrm{K}_{\text {sp }}\) of \(\mathrm{CaCO}_{3}\) is \(5 \times 10^{-9} \mathrm{M}^{2}\), the \(\left[\mathrm{CO}_{3}^{2-}\right]\) in the resulting solution is (a) \(5 \times 10^{-8} \mathrm{M}\) (b) \(5 \times 10^{-9} \mathrm{M}\) (c) \(5 \times 10^{-6} \mathrm{M}\) (d) \(5 \times 10^{-7} \mathrm{M}\)

Which of the following are wrong statements? (a) \(\mathrm{K}_{\mathrm{i}}\) is always constant and equal to \(10^{-14}\) (b) \(\mathrm{pH}+\mathrm{pOH}=\mathrm{pK}_{w}\) at all temperature (c) Salts of strong acid and strong base undergo hydrolysis (d) Addition of \(\mathrm{CH}_{3} \mathrm{COONa}\) to acetic acid solution decreases the \(\mathrm{pH}\) of solution of acetic acid.

An acid-base indicator has \(\mathrm{K}=3.0 \times 10^{-5} .\) The acid form of the indicator is red and the basic form is blue. The \(\left[\mathrm{H}^{+}\right]\)required to change the indicator from \(75 \%\) red to \(75 \%\) blue is (a) \(8 \times 10^{-5} \mathrm{M}\) (b) \(9 \times 10^{-5} \mathrm{M}\) (c) \(1 \times 10^{-5} \mathrm{M}\) (d) \(3 \times 10^{-4} \mathrm{M}\)

The solubility product of \(\mathrm{AgI}\) at \(25^{\circ} \mathrm{C}\) is \(1.0 \times 10^{-16}\) \(\mathrm{mol}^{2} \mathrm{~L}^{-2}\). The solubility of AgI in \(10^{-4} \mathrm{~N}\) solution of \(\mathrm{KI}\) at \(25^{\circ} \mathrm{C}\) is (in \(\mathrm{mol} \mathrm{L}^{-1}\) ) (a) \(1.0 \times 10^{-10}\) (b) \(1.0 \times 10^{-8}\) (c) \(1.0 \times 10^{-16}\) (d) \(1.0 \times 10^{-12}\)
See all solutions

Recommended explanations on Chemistry Textbooks

Making Measurements

Read Explanation

The Earths Atmosphere

Read Explanation

Chemical Analysis

Read Explanation

Physical Chemistry

Read Explanation

Chemical Reactions

Read Explanation

Nuclear Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.