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The elevation in boiling point for \(13.44 \mathrm{~g}\) of \(\mathrm{CuCl}_{2}\) dissolved in \(1 \mathrm{~kg}\) of water as solvent will be \(\left(\mathrm{K}_{\mathrm{b}}=0.52 \mathrm{~kg} / \mathrm{J}\right.\), molar mass of \(\left.\mathrm{CuCl}_{2}=134.4 \mathrm{~g} / \mathrm{mol}\right)\) (a) \(0.05\) (b) \(0.10\) (c) \(0.16\) (d) \(0.20\).

Short Answer

Expert verified
The boiling point elevation is 0.16, corresponding to option (c).

Step by step solution

01

Identify Known Values

We know the following values for the calculation:- Mass of solute (CuCl鈧): \(m = 13.44 \text{ g}\).- Mass of solvent (water): \(1 \text{ kg}\).- Molar mass of CuCl鈧: \(M = 134.4 \text{ g/mol}\).- Boiling point elevation constant, \(K_b = 0.52 \text{ K kg/mol}\).
02

Calculate Moles of Solute

To find the moles of CuCl鈧, use the formula: \[ n = \frac{m}{M} \]Substitute the known values:\[ n = \frac{13.44 \text{ g}}{134.4 \text{ g/mol}} = 0.1 \text{ mol}\]
03

Determine Van't Hoff Factor

CuCl鈧 dissociates into 3 ions: Cu虏鈦 and 2Cl鈦. Therefore, the Van't Hoff factor \(i\) is 3.
04

Calculate Boiling Point Elevation

Use the boiling point elevation formula:\[ \Delta T_b = i \cdot K_b \cdot m \]Where \(m\) (molality) is calculated by dividing moles of solute by mass of solvent in kilograms:\[ m = \frac{0.1 \text{ mol}}{1 \text{ kg}} = 0.1 \text{ mol/kg}\]Substitute into the formula:\[ \Delta T_b = 3 \cdot 0.52 \cdot 0.1 = 0.156 \approx 0.16\]
05

Choose the Correct Answer

Based on the calculated boiling point elevation, the answer matches option (c) 0.16.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Boiling Point Elevation
Boiling point elevation is a colligative property. This means it depends on the number of solute particles in the solution, not the type of particles. When a non-volatile solute is added to a solvent, the boiling point of the resulting solution is higher than that of the pure solvent. The phenomenon occurs because the solute particles disrupt solvent molecule interactions, requiring more energy (higher temperature) to boil the liquid.

The formula to calculate the boiling point elevation, \( \Delta T_b \), is given by:
  • \( \Delta T_b = i \cdot K_b \cdot m \)
where:
  • \( i \) is the Van't Hoff factor, representing the number of particles into which the solute dissociates.
  • \( K_b \) is the ebullioscopic constant of the solvent, providing the boiling point elevation per unit molality.
  • \( m \) is the molality of the solution.
By using this formula, you can predict how much the boiling point of the solvent will increase when a certain quantity of solute is dissolved into it.
Van't Hoff Factor
The Van't Hoff factor, denoted as \( i \), is essential in understanding colligative properties. It corrects for the actual number of particles present in the solution after a solute dissolves. The Van't Hoff factor is particularly important when dealing with ionic compounds, which dissociate into multiple ions in solution.

For a non-electrolyte, which does not dissociate, \( i \) is typically 1. However, for electrolytes like \( \text{CuCl}_2 \), which dissociates into three ions (one \( \text{Cu}^{2+} \) ion and two \( \text{Cl}^{-} \) ions), \( i \) becomes 3. This indicates that each molecule of \( \text{CuCl}_2 \) produces three particles in solution.
  • It's calculated as: \( i = \text{number of particles after dissociation} / \text{number of original formula units} \).
Using the Van鈥檛 Hoff factor helps provide more accurate measurements and predictions for how the solute influences colligative properties like boiling point elevation and freezing point depression.
Molality
Molality is a concentration measure that is especially useful in colligative property calculations. It is defined as the number of moles of solute divided by the mass of the solvent in kilograms. Unlike molarity, which depends on volume, molality is based on mass, making it unaffected by temperature changes.

The formula to find molality \( m \) is:
  • \( m = \frac{\text{moles of solute}}{\text{mass of solvent in kg}} \)
In the exercise provided, the molality of the \( \text{CuCl}_2 \) solution was calculated as:
  • The moles of \( \text{CuCl}_2 \) were found to be 0.1 mol.
  • The mass of the solvent (water) is 1 kg.
  • Thus, \( m = \frac{0.1}{1} = 0.1 \text{ mol/kg} \).
Molality provides a reliable way to express concentration when calculating boiling point elevation, ensuring consistent results regardless of environmental conditions.

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