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Which one of the following forms a colourless solution in aqueous medium? (a) \(\mathrm{V}^{3+}\) (b) \(\mathrm{Cr}^{3+}\) (c) \(\mathrm{Ti}^{3+}\) (d) \(\mathrm{Sc}^{3+}\) Atomic number \(\mathrm{Sc}=21, \mathrm{Ti}=22, \mathrm{~V}=23, \mathrm{Cr}=24\)

Short Answer

Expert verified
Sc鲁鈦 forms a colorless solution in water.

Step by step solution

01

Understand the Color Conditions

Ions are typically colorless in an aqueous medium if they have completely filled or completely empty d-orbitals. This is because electronic transitions between d-orbitals, which give rise to color, are not possible in these cases.
02

Analyze Electronic Configuration

We first identify the electronic configurations of each metal in its +3 oxidation state by removing 3 electrons from the neutal atom configuration. - Scandium (Sc): Atomic number = 21, Configuration = [Ar] 3d鹿 4s虏. For Sc鲁鈦, the configuration becomes [Ar]. - Titanium (Ti): Atomic number = 22, Configuration = [Ar] 3d虏 4s虏. For Ti鲁鈦, the configuration becomes [Ar] 3d鹿. - Vanadium (V): Atomic number = 23, Configuration = [Ar] 3d鲁 4s虏. For V鲁鈦, the configuration becomes [Ar] 3d虏. - Chromium (Cr): Atomic number = 24, Configuration = [Ar] 3d鈦 4s鹿. For Cr鲁鈦, the configuration becomes [Ar] 3d鲁.
03

Identify the Colorless Configuration

The Sc鲁鈦 ion has the electronic configuration [Ar], indicating it has empty d-orbitals (3d鈦 configuration), which do not allow for d-d electronic transitions and therefore do not exhibit color. In contrast, Ti鲁鈦, V鲁鈦, and Cr鲁鈦 ions have partially filled d-orbitals, contributing to color formation.
04

Verify Answer

Since Sc鲁鈦 has an electron configuration with empty d-orbitals, it will form a colorless solution in an aqueous medium. Confirming the consistency between the observed and theoretical conditions for colorlessness.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Colorless Solution
A colorless solution is one that does not exhibit any apparent color when viewed in an aqueous medium. In the context of transition metal ions, the appearance of color is heavily influenced by the arrangement and condition of d-orbitals. When d-orbitals are completely empty or fully filled, there's no available route for electronic transitions that typically produce color. These transitions usually happen as electrons jump between energy levels within these d-orbitals. Without them, the ion absorbs no visible light to show any particular color and hence appears colorless.
This is why Sc鲁鈦, which has an electronic configuration that leads to an empty set of d-orbitals, appears colorless in a solution. Since there are no electrons in its 3d-orbital to make any transitions, there are no light absorption events that would impart color.
d-Orbital Filling
The concept of d-orbital filling concerns the distribution of electrons within the d-sub shell of transition metal ions. A d-orbital can hold up to 10 electrons given its five specific orbitals. How these electrons fill these orbitals strongly influences the properties of the ions, particularly their color.
  • If a d-orbital is completely empty (as in Sc鲁鈦), no electronic transitions can occur, which results in a colorless solution.
  • Similarly, if a d-orbital is completely filled (d鹿鈦 configuration), it will also typically result in a colorless compound because no further electronic transitions are possible.
  • Partial filling (such as in Ti鲁鈦, V鲁鈦, and Cr鲁鈦) usually allows for electronic transitions, which can absorb certain wavelengths of light and impart color to the solution.
The observed color is the result of these transitions not being available, which fundamentally relates to changes in energy levels within these d-orbitals.
Transition Metal Ions
Transition metals are unique in their ability to form ions with various oxidation states, primarily due to the involvement of d-orbitals. They reside in the central block of the periodic table, and are characterized by having an incomplete d-sub shell in one of their common oxidation states.
These metals can lose electrons to form positively charged ions. In the +3 oxidation state, electrons are typically removed from the s-orbital and then the d-orbitals. The specific configuration after this removal determines the behavior of the ion in a solution.
  • For Scandium ( 3^+ or Sc鲁鈦), removal of its three outermost electrons results in an empty d-orbital, leading to a colorless solution.
  • Titanium, Vanadium, and Chromium form partially filled d-orbitals in their respective +3 states, each contributing to a characteristic colored solution because of potential d-d electronic transitions.
Recognizing these patterns helps in predicting the color of solutions containing these metal ions and understanding their chemical behavior.

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