/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 140 Match the following Column-I ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Match the following Column-I (a) \([\mathrm{Ar}] 3 \mathrm{~d}^{\mathrm{s}} 4 \mathrm{~s}^{2}\) (b) \([\mathrm{Ar}] 3 \mathrm{~d}^{10}\) (c) \([\mathrm{Ar}] 3 \mathrm{~d}^{1}\) (d) \([\mathrm{Ar}] 3 \mathrm{~d}^{9}\) Column-II (p) \(\mathrm{Cu}^{2+}\) (q) \(\mathrm{Zn}^{2+}\) (r) \(\mathrm{T}_{1}^{+3}\) (s) \(\mathrm{Cu}^{+}\) (t) Ni

Short Answer

Expert verified
(a)-(t), (b)-(q), (c)-(r), (d)-(s).

Step by step solution

01

Understanding Electron Configurations

First, we need to understand the given electron configurations and match them with possible ions or elements. The configuration \( [\mathrm{Ar}] 3 \mathrm{d}^{\mathrm{s}} 4 \mathrm{s}^{2} \) indicates that the element is in the first row of transition metals, specifically involving the 3d subshell as it's filled after 4s. The correct match depends on identifying the electron count for specific ions.
02

Analyze Configuration (a)

The electron configuration in (a) \( [\mathrm{Ar}] 3 \mathrm{d}^{\mathrm{s}} 4 \mathrm{s}^{2} \) corresponds to nickel (Ni) with \( 3d^{8} \) electrons and \( 4s^{2} \) for a neutral atom. Therefore, the correct match is (t) Ni.
03

Analyze Configuration (b)

(b) \( [\mathrm{Ar}] 3 \mathrm{d}^{10} \) corresponds to a fully filled d subshell. This configuration matches \( \mathrm{Zn}^{2+} \), as zinc loses two electrons from the \( 4s^{2} \) to form the ion. Therefore, the correct match for (b) is (q) \( \mathrm{Zn}^{2+} \).
04

Analyze Configuration (c)

(c) \[ [\mathrm{Ar}] 3 \mathrm{d}^{1} \] corresponds to only one electron in the 3d subshell. This would be the configuration for an ion formed by removal of electrons to leave a single d electron. The match is likely to be (r) \( \mathrm{T}_{1}^{+3} \).
05

Analyze Configuration (d)

(d) \[ [\mathrm{Ar}] 3 \mathrm{d}^{9} \] indicates a situation most fitting of copper's electronic reduction. For \( \mathrm{Cu}^+ \), the electronic configuration would reduce by losing one electron from \( 4s^{1} \) to remain most stable, hence it matches (s) \( \mathrm{Cu}^{+} \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Transition Metals
Transition metals are elements found in the center of the periodic table, specifically in groups 3 to 12. These metals have a unique ability to form a wide variety of oxidation states due to their partially filled d sub-shells. Generally, the electron configuration of transition metals can be intriguing as they initially fill the 4s orbital before starting to fill the 3d sub-shell. This can sometimes seem counterintuitive to students.

These metals include elements such as iron, copper, and nickel, and they are known for their remarkable properties like malleability, corrosion resistance, and the ability to conduct electricity. These elements play significant roles in many industrial applications, such as in the fabrication of alloys and in catalysis for chemical reactions. Understanding how their electron configurations influence their properties and behaviors underlies much of inorganic chemistry.
Matching Electron Configurations
Electron configurations can tell us a lot about the chemical properties and behavior of an element or ion. Matching these configurations helps us to identify specific substances or ions. Upon examining an electron configuration, we should first identify the number of electrons, then relate that to the position in the periodic table.

For instance, the configuration \[\mathrm{Ar}] 3 \mathrm{d}^{10} \] is fully filled, suggesting that it belongs to an ionized form of zinc, such as \mathrm{Zn}^{2+}\, which loses its \[4s^2\] electrons. \[\mathrm{Ar}] 3 \mathrm{d}^{9}\] is associated with \mathrm{Cu}^+\, indicating a subtraction of one electron from its copper parent atom. These exercises train students to understand how electronic structures change when atoms gain or lose electrons.
Ionic Charges
Ionic charges occur due to electrons being transferred between atoms, leading to an imbalance in protons and electrons. This results in an atom becoming positively or negatively charged. The number of electrons lost or gained determines the magnitude of the charge on the ion.

For transition metals, the ionic charge can vary since they can lose different numbers of electrons from their s and d orbitals. For example, zinc typically forms \mathrm{Zn}^{2+}\ by losing its two \[4s\] electrons. Understanding these charges is crucial for predicting how ions will interact in chemical reactions, as they determine the reactivity and the types of bonds an ion will form.
Electron Removal in Ions
When forming ions, the removal of electrons involves subtracting from the outermost sub-shell first. In transition metals, this typically involves the 4s electrons being removed prior to any 3d electrons, despite 4s being filled before the 3d sub-shell.

This concept is particularly key for forming transition metal cations. For instance, when forming \(\mathrm{Cu}^{+}\), one electron is removed from the \[4s\] rather than the \[3d\]. This is because electrons in the 3d sub-shell remain more stable and are less likely to be removed in the initial ionization stages when compared to 4s electrons. The proper understanding of electron removal is significant when predicting and explaining the stability and formation of specific ions in both physical and chemical properties.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Energy of H-atom in the ground state is \(-3.6 \mathrm{eV}\), hence energy in the second excited state is (a) \(-6.8 \mathrm{eV}\) (b) \(-3.4 \mathrm{eV}\) (c) \(-1.51 \mathrm{eV}\) (d) \(-4.53 \mathrm{eV}\)

If a source of power \(4 \mathrm{Kw}\) produces \(10^{20}\) photon Per second, the radiation belongs to a part of the spectrum called (a) \(\gamma\)-Rays (b) U.V Rays (c) Microwaves (d) X-Rays

The frequency of radiation emitted when the electron falls from \(\mathrm{n}=4\) to \(\mathrm{n}=1\) in a hydrogen atom will be (Given ionization energy of \(\mathrm{H}=2.18 \times 10^{18} \mathrm{~J}\) atom \(^{-1}\) and \(\mathrm{h}=6.625 \times 10^{-34} \mathrm{Js}\) ) (a) \(1.54 \times 10^{15} \mathrm{~s}^{-1}\) (b) \(1.03 \times 10^{15} \mathrm{~s}^{-1}\) (c) \(3.08 \times 10^{15} \mathrm{~s}^{-1}\) (d) \(2.00 \times 10^{15} \mathrm{~s}^{-1}\)

The energy of second Bohr orbit of the hydrogen atom is \(-328 \mathrm{~kJ} \mathrm{~mol}^{-1}\), hence the energy of fourth bohr orbit would be (a) \(-164 \mathrm{~kJ} \mathrm{~mol}^{-1}\) (b) \(-41 \mathrm{~kJ} \mathrm{~mol}^{-1}\) (c) \(-82 \mathrm{~kJ} \mathrm{~mol}^{-1}\) (d) \(-1312 \mathrm{~kJ} \mathrm{~mol}^{-1}\)

Which one of the following sets of ions represents the collection of isoelectronic species? (a) \(\mathrm{K}+\mathrm{Ca}^{2+}, \mathrm{Sc}^{3+}, \mathrm{Cl}^{-}\) (b) \(\mathrm{Na}^{+}, \mathrm{Ca}^{2+}, \mathrm{Sc}^{3+}, \mathrm{F}^{-}\) (c) \(\mathrm{K}^{+}, \mathrm{Cl}^{-}, \mathrm{Mg}^{2+}, \mathrm{Sc}^{3+}\) (d) \(\mathrm{Na}^{+} \mathrm{Mg}^{2+}, \mathrm{Al}^{3+}, \mathrm{Cl}^{-}\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.