Chapter 34: Problem 98
A substance on treatment with dilute \(\mathrm{H}_{2} \mathrm{SO}_{4}\) liberates a colourless gas which produces (i) turbidity with baryta water and (ii) turns acidified dichromate solution green. These reactions indicate the presence of (a) \(\mathrm{CO}_{3}^{2-}\) (b) \(\mathrm{S}^{2-}\) (c) \(\mathrm{SO}_{3}^{2-}\) (d) \(\mathrm{NO}_{2}^{-}\)
Short Answer
Step by step solution
Analyze the Reaction with Dilute H2SO4
Reaction with Baryta Water Test
Dichromate Solution Test
Identify the Substance
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Reactions with Sulfuric Acid
- \( \mathrm{CO}_3^{2-} + \mathrm{H}_2\mathrm{SO}_4 \rightarrow \mathrm{CO}_2 + \mathrm{H}_2\mathrm{O} + \mathrm{SO}_4^{2-} \)
- \( \mathrm{SO}_3^{2-} + \mathrm{H}_2\mathrm{SO}_4 \rightarrow \mathrm{SO}_2 + \mathrm{H}_2\mathrm{O} + \mathrm{SO}_4^{2-} \)
Gas Identification Tests
- \( \mathrm{CO}_2 + \mathrm{Ba(OH)_2} \rightarrow \mathrm{BaCO}_3 + \mathrm{H}_2\mathrm{O} \)
Another test involves an acidified dichromate solution. This test identifies gases capable of reducing dichromate ions. Sulfur dioxide \( \mathrm{SO}_2 \) is one such gas that reduces dichromate \( \mathrm{Cr}_2\mathrm{O}_7^{2-} \) to chromium \( \mathrm{Cr}^{3+} \), turning the solution from orange to green:
- \( \mathrm{SO}_2 + \mathrm{Cr}_2\mathrm{O}_7^{2-} + 2\mathrm{H}^+ \rightarrow 2\mathrm{Cr}^{3+} + \mathrm{SO}_4^{2-} + \mathrm{H}_2\mathrm{O} \)
Chemical Reaction Analysis
For instance, given the options in the exercise, understanding the properties and behaviors of carbonate \( \mathrm{CO}_3^{2-} \), sulfide \( \mathrm{S}^{2-} \), sulfite \( \mathrm{SO}_3^{2-} \), and nitrite \( \mathrm{NO}_2^{-} \) ions is key.
- Carbonates react to release \( \mathrm{CO}_2 \).
- Sulfites release \( \mathrm{SO}_2 \).
- Sulfides form \( \mathrm{H}_2\mathrm{S} \).
- Nitrites generally do not yield a colorless gas with sulfuric acid.