/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 135 To the aqueous solution of the s... [FREE SOLUTION] | 91影视

91影视

To the aqueous solution of the salt acidified potassium permanganate is added and its colour is discharged. It indicates the absence of (a) \(\mathrm{Sn}^{2+}\) (b) \(\mathrm{Be}^{2+}\) (c) \(\mathrm{Fe}^{2+}\) (d) \(\mathrm{NO}_{3}\)

Short Answer

Expert verified
The absence of \( \mathrm{Be}^{2+} \) is indicated.

Step by step solution

01

Understanding the Reaction

When acidified potassium permanganate ( KMnO鈧) is added to a solution, it can act as an oxidizing agent. The typical permanganate ion ( MnO鈧勨伝) in acidic conditions is reduced to colorless Mn虏鈦, which indicates the presence of reducing agents. First, let's express the idea that KMnO鈧 discharging its color implies oxidation occurred in the solution.
02

Identifying Potential Reduction Partners

In the question, we need to determine which ion's absence is indicated when the KMnO鈧 solution's color is discharged. When the purple color of KMnO鈧 fades, it means a reaction occurred in which MnO鈧勨伝 was reduced. This suggests that there has been an oxidation of an element in the solution.
03

Analyzing the Given Ions

We need to analyze each of the given ions: 1. Sn虏鈦 ions can be oxidized to Sn鈦粹伜. 2. Fe虏鈦 ions can be oxidized to Fe鲁鈦. 3. NO鈧冣伝 ions are typically already in a stable oxidized state and do not have further typical oxidation in aqueous reactions. 4. Be虏鈦 ions do not typically undergo any oxidation reaction as they are stable.
04

Conclusion from Oxidation Potentials

Oxidation reactions with acidified KMnO鈧 suggest that Sn虏鈦 and Fe虏鈦 would discharge the color of KMnO鈧 since they can be oxidized. However, Be虏鈦 and NO鈧冣伝 do not typically undergo such reactions. Thus, the absence of the ion which does not react and does not cause the color discharge would indicate Be虏鈦.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oxidizing Agent
An oxidizing agent is a substance that has the ability to accept electrons from another substance. This process makes it crucial in chemical reactions, especially those involving redox, or reduction-oxidation, mechanisms. In simpler terms, when an oxidizing agent gains electrons, it prompts another substance in the reaction to lose electrons, which is what we call oxidation.

In the context of potassium permanganate ( KMnO鈧 ), it acts as a strong oxidizing agent, especially when in acidic conditions. The permanganate ion ( MnO鈧勨伝 ) is reduced to Mn虏鈦 as it accepts electrons from a reducing agent present in the solution it is added to. This reduction is visually noticeable because the vivid purple color of KMnO鈧 disappears when it is reduced.

When trying to determine the absence of a certain ion based on this reaction, such as in the exercise, understanding the role of oxidizing agents helps to explain why some ions can discharge the purple color of KMnO鈧 while others do not.

To sum up, the oxidizing agent plays a pivotal role in orchestrating the flow of electrons between substances, fundamentally driving the chemical reaction forward.
Reduction Reaction
A reduction reaction is a process where a substance gains electrons, resulting in a decrease in its oxidation state. This is the converse of oxidation, where a substance loses electrons. The two processes are intimately linked, together known as redox reactions.

In the exercise related to potassium permanganate, the reduction reaction involves MnO鈧勨伝 ions gaining electrons, thereby reducing to Mn虏鈦 . This reduction is linked to the oxidation of another substance in the solution, such as Sn虏鈦 or Fe虏鈦 ions, which lose electrons. The reduction of MnO鈧勨伝 is why the characteristic purple color of the solution fades when the reaction takes place.

Reduction reactions are typically indicated by a decrease in oxidation number, and are essential for balancing chemical equations involving redox processes. They help in determining which elements or ions are acting as reducing agents by donating electrons. Understanding this concept is key to exploring the interactions and outcomes of reactions involving oxidizing agents like potassium permanganate.
Oxidation Potential
Oxidation potential refers to the likelihood or tendency of a substance to lose electrons during a chemical reaction. It is often measured in volts and can be used to predict which substances will undergo oxidation in a given chemical reaction.

To grasp oxidation potential with potassium permanganate reactions, think of it as an indicator of how easily Sn虏鈦 , Fe虏鈦 , or any other potential reducing agents in the solution can give up electrons to the oxidizing agent. KMnO鈧 is very potent because it has a high oxidation potential, in the presence of acidic conditions, allowing it to oxidize various ions effectively.

When comparing oxidation potentials, ions like Sn虏鈦 and Fe虏鈦 have potentials that favor their oxidation to higher states like Sn鈦粹伜 and Fe鲁鈦 . On the other hand, Be虏鈦 and NO鈧冣伝 have lower oxidation potentials in these situations, meaning they are less likely to be oxidized.

This concept helps chemists predict not only which ions will react in the presence of an oxidizing agent but also which will remain unchanged due to their reluctance to undergo oxidation under given conditions. Understanding this concept helps solve and interpret exercises based on redox chemistry.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.