Chapter 34: Problem 101
Which one among the following pairs of ions can not be separated by \(\mathrm{H}_{2} \mathrm{~S}\) in dilute hydrochloric acid? (a) \(\mathrm{Bi}^{3+}, \mathrm{Sn}^{4+}\) (b) \(\mathrm{Al}^{3+}, \mathrm{Hg}^{2+}\) (c) \(\mathrm{Zn}^{2+}, \mathrm{Cu}^{2+}\) (d) \(\mathrm{Ni}^{2+}, \mathrm{Cu}^{2+}\)
Short Answer
Step by step solution
Understanding Separation by H2S
Analyze Ion Pair (a)
Analyze Ion Pair (b)
Analyze Ion Pair (c)
Analyze Ion Pair (d)
Conclusion and Answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Precipitation with H2S
The choice of using \(\mathrm{H}_{2}\mathrm{~S}\) hinges on the differential solubility of various metal sulfides in acidic conditions. Metals such as bismuth and copper readily form sulfides which are less soluble and precipitate out. This means they can be separated from ions like aluminum which do not form such precipitates.
Overall, by using this method, mixtures of ions can be analyzed by observing which ions form precipitates under specific conditions of acidity.
Metal Sulfides
Some common metal sulfides like \(\mathrm{CuS}\) (copper sulfide) and \(\mathrm{HgS}\) (mercury sulfide) are known for their low solubility in water, which makes them useful for precipitative separation methods. The formation of these sulfides depends heavily on both the specific metal involved and the conditions under which the reaction occurs, such as the pH and concentration of hydrogen ions.
Metal sulfides are crucial in separating ions because their formation can be influenced by changing the acidity of the solution, allowing chemists to isolate specific ions based on their unique chemical properties.
Solubility in Acid
In acidic conditions, some metal sulfides like those of zinc (\(\mathrm{ZnS}\)) and copper (\(\mathrm{CuS}\)) exhibit very low solubility, resulting in their precipitation. This property is exploited in the separation of metal ions in mixtures, where acids are used to affect the solubility of different metal sulfides differently, allowing for the separation of these ions based on whether they form a precipitate or remain dissolved.
The pH of the solution, therefore, plays a pivotal role in determining the outcome of such separation processes, with some sulfides only precipitating under specific acidic conditions.
Analytical Chemistry
These techniques rely on the principles of solubility and chemical reactivity to achieve the separation of different substances. Metal ions can be differentiated by their unique chemical reactions, like forming distinct metal sulfides that are insoluble under certain conditions.
Such methods are invaluable in laboratory settings where precise identification and separation of components are needed, such as in qualitative analysis of unknown mixtures or in ensuring the purity of processed materials.
- Key tools in analytical chemistry include titration, spectroscopy, and chromatography alongside precipitation techniques.
Inorganic Chemistry in JEE
Understanding how metal ions react under different conditions, such as with sulfur compounds or in varying acidities, is crucial for solving many problems presented in this competitive exam. Students are expected to grasp the reasons behind solubility differences and the principles guiding analytical techniques to succeed in this subject.
Preparing for JEE often involves practicing problems that require the application of these concepts in realistic scenarios, emphasizing both theoretical understanding and practical application skills. Teaching strategies may include focusing on problem-solving techniques and providing detailed explanations of reactions and chemical properties.