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Which of the following cannot give iodomertic titration? (a) \(\mathrm{Cu}^{2+}\) (b) \(\mathrm{Fe}^{3+}\) (c) \(\mathrm{Ag}^{+}\) (d) \(\mathrm{Pb}^{2+}\)

Short Answer

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(c) \(\mathrm{Ag}^{+}\) cannot give iodomertic titration.

Step by step solution

01

Understanding Iodometric Titration

Iodometric titration involves the reaction of iodine with a substance to determine its concentration. It is an indirect method in which iodine is either liberated from an iodide solution or consumed by the substance being titrated. The principle is based on the oxidation-reduction reactions involving iodine.
02

Identifying Redox-Active Ions

In iodometric titration, the ions that are titratable are those that can participate in redox reactions involving iodine. Typically, \(\mathrm{Cu}^{2+}\) and \(\mathrm{Fe}^{3+}\) are classic examples that can react in these redox processes where copper(II) can be reduced and iron(III) can be oxidized or reduced.
03

Potential for Redox Reaction with Iodine

Among the given options, \(\mathrm{Cu}^{2+}\) and \(\mathrm{Fe}^{3+}\) actively participate in redox chemistry that suits iodometric titration. Conversely, \(\mathrm{Ag}^{+}\) and \(\mathrm{Pb}^{2+}\) ions don't typically undergo the necessary changes to fit the criteria effectively without side reactions or direct participation with iodine.
04

Conclusion

Given the nature of iodometric titration and the requirements for redox reaction, \(\mathrm{Ag}^{+}\) is the ion that typically would not engage in a straightforward redox reaction with iodine in this context, making it the incorrect option for iodometric titration.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Redox Reactions
Redox reactions are a fundamental part of chemistry that involve the transfer of electrons between substances. These reactions are characterized by one substance being oxidized, where it loses electrons, and another being reduced, gaining those electrons. In the context of iodometric titration, redox reactions are pivotal. The titration relies on the ability of a substance to undergo an oxidation-reduction process with iodine. - During the titration, iodine can be freed or it can react with other substances. - This reaction alters the oxidation state of the ions involved. - Recognizing which ions can actively participate in these electron exchanges is crucial. Understanding redox reactions helps in predicting the outcome of the titration process and identifying suitable ions for iodometric methods.
Oxidation-Reduction
Oxidation-reduction, often shortened to redox, is the key process in which iodometric titrations occur. The titration exploits the different tendencies of ions and iodine to either gain or lose electrons. Oxidation is the process where a molecule, atom, or ion loses electrons, while reduction involves a gain of electrons. In iodometric titrations, iodine often takes part as either an oxidizing or reducing agent depending on the reaction conditions.- Substances like \(\mathrm{Cu}^{2+}\) and \(\mathrm{Fe}^{3+}\) are perfect examples of ions that participate readily in such redox transfers. - The ion \(\mathrm{Cu}^{2+}\), for instance, can be reduced to \(\mathrm{Cu}^{+}\), while \(\mathrm{Fe}^{3+}\) can undergo reduction to \(\mathrm{Fe}^{2+}\) or oxidation to higher oxidation states.The success of an iodometric titration depends heavily on selecting ions that can undergo these redox transformations effectively.
Chemistry Education
In the sphere of chemistry education, understanding iodometric titration and the principles behind redox reactions deepens students' knowledge of chemical processes. This concept is an excellent educational tool as it combines practical laboratory techniques with theoretical knowledge of oxidation and reduction. - Students learn how to safely handle chemicals and perform accurate measurements. - It encourages critical thinking as students must deduce which ions can participate in the redox reactions. - Grasping iodometric titration also helps in understanding broader topics such as electrochemistry and analytical chemistry. Teaching these concepts can prepare students for further studies in chemistry and related fields, enhancing both theoretical understanding and practical skills.
Transition Metal Ions
Transition metal ions are central to many chemical processes due to their variable oxidation states, making them ideal candidates in redox and iodometric titrations. These metals typically exhibit a range of oxidation states, which enables them to easily participate in electron transfer processes.- Metals like copper (\(\mathrm{Cu}^{2+}\)) and iron (\(\mathrm{Fe}^{3+}\)) are classic examples that have versatile redox behaviors.- They are often used in titration because they can change oxidation states under different conditions. - The readiness of these ions to undergo oxidation or reduction makes them suitable for iodometric procedures.Understanding the properties of transition metals enables chemists to harness their reactivity for various analyses, both in academic and industrial contexts.

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Most popular questions from this chapter

An aqueous solution containing \(\mathrm{S}^{2-}\) ions will not give (a) White precipitate with \(\mathrm{CaCO}_{3}\) suspension (b) Purple colour with sodium thiosulphate solution (c) A yellow precipitate with the suspension of \(\mathrm{CdCO}_{3}\) in water (d) Black precipitate with lead acetate solution

If a compound reacts with \(\mathrm{HNO}_{2}\) but does not form a dye with \(\beta-\) naphthol. The compound may contain (a) \(\mathrm{NH}_{2}\) group as the main functional group (b) \(\mathrm{NH}_{2}\) group in the side chain (c) The compound may have a phenolic group (d) Both (a) and (b)

Match the following List-I a. \(\mathrm{AgNO}_{3}+\mathrm{NaCNS}\) b. \(\mathrm{AgNO}_{3}+\mathrm{Na}_{3} \mathrm{PO}_{4}\) c. \(\mathrm{AgNO}_{3}+\mathrm{K}_{2} \mathrm{CrO}_{4}\) d. \(\mathrm{AgNO}_{3}+\mathrm{Na}_{2} \mathrm{~S}\) List-II (p) White (q) Black (r) Brick red 1 (s) Yellow

A solution of a metal ion when treated with KI gives a red precipitate which dissolves in excess KI to give a colourless solution. Moreover, the solution of metal ion on treatment with a solution of cobalt(II) thiocyanate gives rise to a deep blue crystalline precipitate. The metal ion is (a) \(\mathrm{Pb}^{2+}\) (b) \(\mathrm{Hg}^{2+}\) (c) \(\mathrm{Cu}^{2+}\) (d) \(\mathrm{Co}^{2+}\)

An aqueous solution of a substance gives a white precipitate on treatment with dil. \(\mathrm{HCl}\) which dissolves on heating. When \(\mathrm{H}_{2} \mathrm{~S}\) is passed through the hot acidic solution, a black precipitate is obtained. The substance is a (a) \(\mathrm{Ag}^{+}\)salt (b) \(\mathrm{Cu}^{2+} \mathrm{salt}\) (c) \(\mathrm{Pb}^{2+}\) salt (d) \(\mathrm{Hg}_{2}{ }^{2+} \mathrm{salt}\)

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