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Which one of the following on reduction with \(\mathrm{NaBH}_{4}\) gives an equimolar mixture of sorbitol and mannitol? (a) mannose (b) glucose (c) xylose (d) fructose

Short Answer

Expert verified
(d) Fructose gives an equimolar mixture of sorbitol and mannitol when reduced.

Step by step solution

01

Understand Reduction with NaBH4

Sodium borohydride (NaBHâ‚„) is a common reducing agent used to reduce ketones and aldehydes to alcohols. When a sugar with a ketone group is reduced, the carbon bearing the ketone group becomes chiral, leading to the formation of epimers.
02

Analyze Each Option

Let's examine the structure of each sugar: (a) Mannose: An aldohexose with an aldehyde group. (b) Glucose: An aldohexose with an aldehyde group. (c) Xylose: An aldopentose with an aldehyde group. (d) Fructose: A ketohexose with a ketone group at C2.
03

Fructose Reduction

Fructose, being a ketohexose, is reduced at its ketone group on C2 by NaBHâ‚„. The reduction of this ketone can create two different alcohols, because it produces two different chiral centers (sorbitol and mannitol), depending on how the hydride ion is added to the carbonyl group.
04

Draw Equimolar Mixture Formation

When NaBHâ‚„ reduces fructose, it does so at the C2 ketone, leading to two possible stereoisomers due to the creation of a new chiral center. These stereoisomers are D-mannitol and D-sorbitol, formed in equimolar quantities, due to symmetrical reduction at the C2 position.
05

Conclusion

Only fructose, with a ketone group, can give an equimolar mixture of sorbitol and mannitol after reduction with NaBHâ‚„, because it forms a new stereogenic center during reduction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reduction with NaBH4
Reduction with sodium borohydride (NaBHâ‚„) is a fundamental concept in carbohydrate chemistry. NaBHâ‚„ acts as a reducing agent, converting carbonyl groups in ketones and aldehydes into alcohol groups. This transformation is particularly important when dealing with sugars. The reducing process involves the addition of hydrogen to the carbonyl carbon, turning it into a hydroxyl group.

In the context of sugars, NaBHâ‚„ reduces the ketone group present in ketohexoses like fructose, transforming them into alcohols. Unlike aldohexoses, such as glucose or mannose, which primarily possess aldehyde groups, ketohexoses have ketone functional groups. As a result, when fructose is reduced, the ketone group on the sugar is transformed, hence creating new chiral centers and resulting in different alcohol products.
Chiral Centers and Epimers
Chiral centers play a critical role in determining the properties and behavior of molecules in chemistry, especially in sugars. A chiral center is a carbon atom bonded to four distinct groups, leading to molecules that are non-superimposable mirror images, known as enantiomers.

When reducing fructose with NaBHâ‚„, a chiral center is introduced at the site of the former ketone group. This happens because the reduction creates two possible alcohol products depending on the direction from which the hydride ion (source of hydrogen from NaBHâ‚„) attacks the carbonyl group. This leads to the formation of two different epimers, sorbitol and mannitol.
  • Epimers are a type of stereoisomer differing only at one chiral center.
  • In this scenario, the creation of these two epimers is why we see an equimolar mixture of sorbitol and mannitol when fructose is reduced.
Ketohexose and Aldose Reduction
Understanding the difference between ketohexoses and aldohexoses is integral to grasping their behavior under reduction. Ketohexoses, such as fructose, contain a ketone group in their structure, while aldohexoses, like glucose and mannose, contain an aldehyde group.

When a ketohexose like fructose undergoes reduction with NaBH₄, the ketone at the second carbon (C2) is targeted. The reduction at this site creates two stereoisomers—D-mannitol and D-sorbitol—due to the creation of a new chiral center. This process results in an equimolar mixture of both stereoisomers, distinguishing it from aldohexoses and aldopentoses like glucose, mannose, or xylose, which do not form such equimolar mixtures under the same conditions. Thus, the reduction of aldoses typically does not yield multiple stereoisomers in equimolar ratios as seen with the ketohexose fructose.

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Most popular questions from this chapter

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