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Chapter 23: Problem 130

For each category of compounds the minimum number of carbons required for optical isomerism to be possible is given. Find the correct match (es). (a) Alkane \(-7\) (b) Alkene \(-6\) (c) Alkyl halide \(-4\) (d) Alkadiene - 7

Short Answer

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(a) 7 carbons for alkane, (b) 6 carbons for alkene, (c) 4 carbons for alkyl halide, (d) 7 carbons for alkadiene.

Step by step solution

01

Understanding Optical Isomerism

Optical isomerism occurs due to the presence of a chiral center in a molecule. A carbon atom can be a chiral center if it is bonded to four different substituents.
02

Minimum Carbon Requirement for Alkanes

For alkanes, to have a chiral center, a branch must involve a carbon atom with four different groups attached. Let's try with 7 carbon atoms: a chiral center can be created in a branched structure, such as in 3-methylhexane.
03

Minimum Carbon Requirement for Alkenes

In alkenes, optical isomerism can arise from restricted rotation around the double bond. The simplest chiral alkene might be an unsymmetrical disubstituted double bond, like 3-methylpent-2-ene, but typically requires 6 carbons for such a configuration.
04

Minimum Carbon Requirement for Alkyl Halides

For alkyl halides, a carbon atom can become a chiral center if bonded to a halogen and three different other groups. An example with 4 carbon atoms is 2-bromobutane, which has a chiral center at the second carbon.
05

Minimum Carbon Requirement for Alkadienes

Alkadienes typically need more complexity for optical isomerism. For certain structures, such as hepta-1,3-diene with specific substitutions, 7 carbon atoms are required to achieve a scenario for chiral centers or cis-trans isomerism.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chiral Center
A chiral center is key to understanding optical isomerism. It is usually a carbon atom bonded to four different substituents or groups, which creates asymmetry in the molecule. This asymmetry is crucial because it allows the molecule to exist in two non-superimposable mirror image forms, known as enantiomers. These enantiomers can rotate plane-polarized light in different directions; one clockwise and the other counterclockwise. This property is essential for the concept of chiral centers.
  • Chiral centers cause molecules to exhibit optical activity
  • Presence of four different groups is necessary for a chiral center
  • Leads to enantiomers, causing different rotations of light
Understanding chiral centers can help us determine if a molecule has optical isomerism potential.
Alkanes
Alkanes are the simplest organic compounds, consisting entirely of single-bonded carbon and hydrogen atoms. While typically not chiral because of their simple structure, they can achieve optical isomerism under certain conditions. To create a chiral alkane, at least one carbon atom must have four different groups attached. In straight-chain alkanes, this requires introducing branches.
  • Typically not chiral due to symmetry
  • Branched alkanes with a chiral center can show optical isomerism
  • Minimum of 7 carbons is often required for complexity
Examples like 3-methylhexane show how alkanes can indeed exhibit optical isomerism.
Alkenes
Alkenes contain carbon-carbon double bonds, which offer a unique structural feature that can result in optical isomerism through cis-trans isomerism and chiral centers from branching. The double bond restricts rotation, and when combined with asymmetrical substitutions, can result in chiral geometries.
  • Double bond leads to restricted rotation, influencing optical isomerism
  • Minimum of 6 carbons can typically allow formation of a chiral alkene
  • Disubstituted alkenes like 3-methylpent-2-ene can be chiral
Understanding these principles helps recognize how alkenes can illustrate optical isomerism.
Alkyl Halides
Alkyl halides are a category of organic compounds where a halogen atom is bonded to an alkane framework. Chiral centers in alkyl halides can be achieved when the halogen attaches to a carbon that has three other different groups. This makes alkyl halides a suitable candidate for studying optical isomerism.
  • Presence of a halogen atom introduces the necessary asymmetry for chiral centers
  • Typically requires 4 carbons for potential chiral center formation
  • Example: 2-bromobutane, where the bromine attachment leads to chirality
Through this, alkyl halides cleverly illustrate how even small structural changes impact optical properties.
Alkadienes
Alkadienes possess two carbon-carbon double bonds. Their complexity can allow optical isomerism to arise not only from chiral centers but also through cis-trans isomerism if the double bonds are appropriately substituted. This makes alkadienes intriguing for studying stereochemistry.
  • Contains two double bonds adding structural complexity
  • 7 carbons are often needed for sufficient complexity for optical isomerism
  • Chirality can result from specific substitution patterns
Certain substitutions in hepta-1,3-diene can result in chiral centers, showcasing the intricate ways in which alkadienes can exhibit optical isomerism.

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Most popular questions from this chapter

The maximum number of carbon atoms arranged linearly in the molecule, \(\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{C}-\mathrm{CH}=\mathrm{CH}_{2}\) are (a) 3 (b) 4 (c) 5 (d) 6

Match the following: List I List II 1\. \(\mathrm{CH}_{3} \mathrm{COOH}\) and \(\mathrm{HCOOCH}_{3}\) (i) metamers 2\. \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{C} \equiv \mathrm{CH}\) and (ii) position isomers \(\mathrm{CH}_{3}-\mathrm{C}=\mathrm{C}-\mathrm{CH}_{3}\) 3\. \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}\) and (iii) tautomers \(\mathrm{CH}_{3}-\mathrm{CH}\left(\mathrm{NH}_{2}\right)-\mathrm{CH}_{3}\) 4\. \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\) and \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{O}\) (iv) functional isomer The correct matching is: \(\begin{array}{llll}1 & 2 & 3 & 4\end{array}\) (a) (iii) (iv) (i) (iv) (b) (i) (ii) (iii) (iv) (c) (iii) (ii) (i) (iv) (d) (iv) (ii) (ii) (iv)

2 -methylpenta- 2,3 -diene is achiral as it has (a) a centre of symmetry (b) a plane of symmetry (c) a \(\mathrm{C}_{2}\) axis of symmetry (d) both centre and a plane of symmetry

How many structural and geometrical isomers are possible for dimethyl cyclohexane? (a) 3,3 (b) 3,6 (c) 6,6 (d) 6,3

How many chiral compounds are possible on monochlorination of \(2-\) methyl butane? [2012] (a) 4 (b) 8 (c) 6 (d) 2
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