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The oxidation number of \(\mathrm{Fe}\) in \(\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4}, \mathrm{Cr}\) in \(\left[\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{3}\left(\mathrm{NO}_{2}\right)_{3}\right]\) and \(\mathrm{Ni}\) in \(\left[\mathrm{Ni}(\mathrm{CO})_{4}\right]\) are respectively (a) \(0,+3,+2\) (b) \(+3,+3,0\) (c) \(+3,0,+3\) (d) \(+2,+3,0\)

Short Answer

Expert verified
The oxidation numbers are respectively +2, +3, and 0 (d).

Step by step solution

01

Determine Oxidation Number for Fe in [Fe(CN)鈧哴鈦粹伝

In the complex \([\mathrm{Fe}(\mathrm{CN})_{6}]^{4-}\), the overall charge is -4. Cyanide \((\mathrm{CN}^-)\) has a charge of -1. There are 6 cyanide ions, contributing \(-1 \times 6 = -6\) to the charge. To balance with the overall charge of -4, the oxidation number of \(\mathrm{Fe}\) must be +2. Thus, for \(\mathrm{Fe}\), we have: \(+2 - 6 = -4\).
02

Determine Oxidation Number for Cr in [Cr(NH鈧)鈧(NO鈧)鈧僝

In the complex \([\mathrm{Cr}(\mathrm{NH}_3)_3(\mathrm{NO}_2)_3]\), the ammonia \((\mathrm{NH}_3)\) ligands are neutral, contributing 0 to the charge. Nitro groups \((\mathrm{NO}_2^- )\) each have a charge of -1, which makes \(-1 \times 3 = -3\). Since there is no overall charge, \(\mathrm{Cr}\)'s oxidation state must balance the -3 from the nitrite ions, so \(\mathrm{Cr}\) is +3. Thus, for \(\mathrm{Cr}\), we have: \(+3 - 3 = 0\).
03

Determine Oxidation Number for Ni in [Ni(CO)鈧刔

In the complex \([\mathrm{Ni}(\mathrm{CO})_{4}]\), carbon monoxide \((\mathrm{CO})\) is a neutral ligand, contributing 0 to the complex's charge. Since the compound is neutral overall, and there are no charges from ligands or the overall complex, the oxidation state of \(\mathrm{Ni}\) must be 0.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coordination Compounds
Coordination compounds are fascinating structures that are composed of a central metal atom or ion bonded to surrounding molecules or ions, known as ligands. These complex entities play a significant role in many chemical processes and have applications ranging from catalysis to pharmaceuticals. A key feature of coordination compounds is their ability to form complex ions, where the central metal ion is bonded to ligands. This union significantly alters the properties of the metal, allowing for unique behaviors and functionalities. Understanding the composition and structure of coordination compounds is crucial in determining properties like oxidation states, magnetism, and color.
Furthermore, these compounds can exhibit various geometric configurations, such as octahedral, tetrahedral, and square planar, depending on the metal and ligands involved. The coordination number, which refers to the number of ligand atoms directly bonded to the central metal, is a critical aspect of their structure. Coordination numbers can vary, typically ranging from two to eight.
Ligands
In coordination chemistry, ligands are molecules or ions that donate a pair of electrons to a central metal atom or ion to form a coordinate bond. The nature of these ligands鈥攚hether they are neutral molecules like water or ammonia, or negatively charged ions like chloride or cyanide鈥攇reatly influences the properties of the entire coordination complex. Ligands have different binding capacities, characterized by terms like monodentate, bidentate, or polydentate, which describe how many points on the ligand can attach to the metal. For example, a monodentate ligand uses one atom to bind, while a bidentate ligand, like ethylenediamine, uses two.
Additionally, the field strength or the ability of a ligand to split the d-orbitals of the central metal ion is another essential characteristic. This affects the color and magnetic properties of the compound, which can be predicted using the spectrochemical series鈥攁 list ordering ligands by their field strength.
Transition Metals Chemistry
Transition metals, found in the d-block of the periodic table, are characterized by their ability to form variable oxidation states and complex geometries with ligands. This property stems from their d-orbitals, which can accommodate different numbers of electrons. In transition metal chemistry, the oxidation state is crucial as it influences the metal's ability to bind with different ligands and participate in chemical reactions. Another interesting feature is their ability to exhibit intensive coloration, which arises from d-d electronic transitions鈥攁 result of electrons jumping between d-orbitals in a process influenced by the ligands around the metal.
  • Transition metals often serve as catalysts in industrial reactions due to their variable oxidation states and ability to stabilize transition states.
  • They play critical roles in biological systems; for example, iron in hemoglobin helps transport oxygen in the blood.
  • Their chemistry is fundamental in developing new materials with specific electronic and magnetic properties.
Overall, the chemistry of transition metals forms a versatile and rich area of study, constantly evolving with new discoveries and innovations.

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Most popular questions from this chapter

Isomerism shown by octahedral complex \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4}\right.\) \(\left.\mathrm{Br}_{2}\right] \mathrm{Cl}\) are (a) geometrical and ionization (b) optical and ionization (c) geometrical and optical (d) only geometrical

How many EDTA (ethylenediamine-tetraacetic acid) molecules are required to make an octahedral complex with a \(\mathrm{Ca}^{2+}\) ion? (a) six (b) three (c) one (d) two

Among \(\left[\mathrm{Ni}(\mathrm{CO})_{4}\right],\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}\) and \(\left[\mathrm{NiCl}_{4}\right]^{2-}\) (a) \(\left[\mathrm{Ni}(\mathrm{CO})_{4}\right]\) and \(\left[\mathrm{NiCl}_{4}\right]^{2}\) are diamagnetic and \(\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2}\) is paramagnetic (b) \(\left[\mathrm{NiCl}_{4}\right]^{2-}\) and \(\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}\) are diamagnetic and \(\left[\mathrm{Ni}(\mathrm{CO})_{4}\right]\) is paramagnetic (c) \(\left[\mathrm{Ni}(\mathrm{CO})_{4}\right]\) and \(\left[\mathrm{NiCN}_{4}\right]^{2-}\) are diamagnetic and \(\left[\mathrm{Ni}(\mathrm{Cl})_{4}\right]^{2-}\) is paramagnetic (d) \(\left[\mathrm{Ni}(\mathrm{CO})_{4}\right]\) is diamagnetic and \(\left[\mathrm{NiCl}_{4}\right]^{2}\) and \(\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}\) are paramagnetic

The 'spin-only' magnetic moment [in units of Bohr magneton \(\left.\left(\mu_{\mathrm{B}}\right)\right]\) of \(\mathrm{Ni}^{2+}\) in aqueous solution would be (Atomic number of \(\mathrm{Ni}=28\) ) (a) \(2.84\) (b) \(4.90\) (c) 0 (d) \(1.73\)

For the complex \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}\) (a) Shape is tetrahedral (b) Hybridization state of central ion is \(\mathrm{sp}^{3}\) (c) Effective atomic number of central ion is 35 (d) Number of unpaired electrons present in the central ion is 1

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