Chapter 16: Problem 90
Which one of the following order is correct for the bond energies of halogen molecules? (a) \(\mathrm{Cl}_{2}>\mathrm{Br}_{2}>\mathrm{I}_{2}\) (b) \(\mathrm{Br}_{2}>\mathrm{Cl}_{2}>\mathrm{I}_{2}\) (c) \(\mathrm{I}_{2}>\mathrm{Cl}_{2}>\mathrm{Br}_{2}\) (d) \(\mathrm{I}_{2}>\mathrm{Br}_{2}>\mathrm{Cl}_{2}\)
Short Answer
Step by step solution
Understand the Concept of Bond Energy
Recall Bond Energy Trend in Halogens
Arrange Halogens Based on Bond Energy
Select the Correct Option
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Halogen Molecules
- Fluorine molecule: egin{align*} F_2 ewline ext{(g)} ewline ext{ ext{}} ewline Example ewline of ewline halogen ewline molecule} ewline }
- Chlorine: Clâ‚‚
- Bromine: Brâ‚‚
- Iodine: Iâ‚‚
Diatomic Molecules
- Chlorine (Clâ‚‚)
- Fluorine (Fâ‚‚)
- Other Halogens
- Iodine (Iâ‚‚, used in water purification and photography)
- Bromine (Brâ‚‚, in flame retardants and agricultural practices)
- .
Chemical Bonding
- Atomic size
- Orbital overlap
- Electronegativity
Periodic Table Trends
- Atomic Size: Decreases from left to right across a period and increases down a group
- Electronegativity: Increases across a period and decreases down a group