/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 Which type of ion does the anhyd... [FREE SOLUTION] | 91影视

91影视

Which type of ion does the anhydrons mixture of KF and HF contain? (a) \(\mathrm{KH}^{+}, \mathrm{F}\) (b) \((\mathrm{KF})^{+}(\mathrm{HF})\) (c) \(\mathrm{K}^{+}, \mathrm{H}^{+}, \mathrm{F}^{-}\) (d) \(\mathrm{K}^{+}, \mathrm{HF}_{2}^{-}\)

Short Answer

Expert verified
The anhydrons mixture of KF and HF contains K鈦 and HF鈧傗伝 ions (Option d).

Step by step solution

01

Understanding Anhydrons Mixture

When dealing with an anhydrons mixture of KF and HF, the lack of water indicates possible unusual ionic forms due to their interactions. Specifically, HF can form hydrogen bonds and change into other ions with fluorides.
02

Analyze KF and HF Ions Individually

Potassium fluoride (KF) forms ions such as K鈦 and F鈦 when dissolved, while hydrogen fluoride (HF) typically forms H鈦 and F鈦 ions, although in particular conditions like in mixtures it can form complex ions or remain as HF.
03

Presence of Complex Ions in the Mixture

In the special conditions of an anhydrons mixture, HF can interact with F鈦 from KF to form a bifluoride ion, HF鈧傗伝, rather than dissociating into H鈦 and F鈦 ions. Therefore, the mixture can involve complex ions like HF鈧傗伝.
04

Identify Correct Ion Composition

Based on the interactions and complex ions formed, the ion composition of the anhydrons mixture of KF and HF commonly includes K鈦 ions and HF鈧傗伝 ions formed by the interaction of HF with F鈦 ions.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Anhydrons Mixture
In chemistry, an "anhydrons mixture" refers to a mixture that does not contain water. When we talk about anhydrous mixtures involving ionic compounds, we consider how these substances interact without water's influence. Specifically, for the mixture of potassium fluoride (KF) and hydrogen fluoride (HF), the absence of water leads to unique interactions.
In a typical aqueous solution, ionic compounds dissociate fully into their respective ions. However, in an anhydrous mixture, the behavior changes. Without water, ions might form unusual species due to direct interaction. For KF and HF, this means potential formation of complex ions. HF can particularly participate in hydrogen bonding or other transformations when interacting with KF. This interaction is crucial because it results in the formation of ions that wouldn't normally exist in a regular aqueous solution.
Keeping these interactions in mind helps us understand the resulting ionic composition present in the mixture.
Bifluoride Ion
The bifluoride ion, represented as \( \text{HF}_2^- \), is a complex ion formed under specific conditions, like in an anhydrous mixture of KF and HF. This ion results from the reaction where hydrogen fluoride (HF) interacts with fluoride ions (F鈦).
  • Formation: In an anhydrous environment, HF does not fully dissociate into H鈦 and F鈦 ions. Instead, a unique reaction occurs. HF can accept another F鈦 ion from KF, forming the bifluoride ion \( \text{HF}_2^- \).
  • Stability: The stabilization comes from hydrogen bonding within the structure between HF molecules and F鈦 ions.
The formation of \( \text{HF}_2^- \) illustrates the remarkable way in which ions can rearrange in the absence of water, showcasing the diverse nature of chemical bonding and interactions.
Dissociation of HF
Hydrogen fluoride (HF) behaves differently in terms of dissociation depending on its environment. In aqueous solutions, HF is recognized for its weak acid properties, not completely dissociating into hydrogen (H鈦) and fluoride (F鈦) ions.
However, in anhydrous conditions, like the mixture with potassium fluoride (KF), HF's dissociation is altered. While some HF molecules might remain intact, others can take part in forming the bifluoride ion \( \text{HF}_2^- \). This interaction limits the production of free H鈦 ions since HF prefers to engage in complex ion formations rather than dissociating completely.
This behavior underscores how the dissociation of HF is heavily influenced by the surrounding environment. In the absence of water, HF interacts in unexpected ways, emphasizing the flexibility and variability in chemical bonding.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The thermal stability order for group 14 halides is (a) \(\operatorname{SnX}_{4}>\mathrm{GeX}_{4}>\mathrm{SiX}_{4}>\mathrm{CX}_{4}\) (b) \(C \mathrm{CX}_{4}^{4}>\mathrm{SiX}_{4}>\mathrm{GeX}_{4}^{4}>\mathrm{SnX}_{4}^{4}\) (c) \(\mathrm{SiX}_{4}^{4}>\mathrm{CX}_{4}^{4}>\mathrm{GeX}_{4}^{4}>\mathrm{Sn} \mathrm{X}_{4}^{4}\) (d) \(C X_{4}^{4}>\operatorname{Sn} X_{4}>G e X_{4}>S i X_{4}^{4}\)

In which of the following arrangements, the sequence is not strictly according to the property written against it? (a) \(\mathrm{HF}<\mathrm{HCl}<\mathrm{HBr}<\mathrm{HI}\) : increasing acid strength (b) \(\mathrm{NH}_{3}<\mathrm{PH}_{3}<\mathrm{AsH}_{3}<\mathrm{SbH}_{3}:\) increasing basic strength (c) \(\mathrm{B}<\mathrm{C}<\mathrm{O}<\mathrm{N}\) : increasing first ionization enthalpy (d) \(\mathrm{CO}_{2}<\mathrm{SiO}_{2}<\mathrm{SnO}_{2}<\mathrm{PbO}_{2}\) : increasing oxidising power

Which one of the following arrangement is in the order of increasing density? (a) \(\mathrm{Na}<\mathrm{K}<\mathrm{Li}\) (b) \(\mathrm{Li}<\mathrm{K}<\mathrm{Na}\) (c) \(\mathrm{K}<\mathrm{Li}<\mathrm{Na}\) (d) \(\mathrm{Li}<\mathrm{Na}<\mathrm{K}\)

The decreasing order of solubility of alkaline earth metal hydroxides \(\left[\mathrm{M}(\mathrm{OH})_{2}\right]\) is given as (a) \(\mathrm{Ba}>\mathrm{Sr}>\mathrm{Ca}>\mathrm{Mg}>\mathrm{Be}\) (b) \(\mathrm{Be}<\mathrm{Mg}<\mathrm{Ca}<\mathrm{Sr}<\mathrm{Ba}\) (c) \(\mathrm{Be}=\mathrm{Mg}>\mathrm{Ca}>\mathrm{Sr}>\mathrm{Ba}\) (d) \(\mathrm{Mg}<\mathrm{Be}<\mathrm{Ca}<\mathrm{Ba}<\mathrm{Sr}\)

Which one of the following orders presents the correct sequence of the increasing basic nature of the given oxides? (a) \(\mathrm{Na}_{2} \mathrm{O}<\mathrm{K}_{2} \mathrm{O}<\mathrm{MgO}<\mathrm{Al}_{2} \mathrm{O}_{3}\) (b) \(\mathrm{Al}_{2} \mathrm{O}_{3}<\mathrm{MgO}<\mathrm{Na}_{2} \mathrm{O}<\dot{\mathrm{K}}_{2} \mathrm{O}\) (c) \(\mathrm{MgO}<\mathrm{K}_{2} \mathrm{O}<\mathrm{Al}_{2} \mathrm{O}_{3}<\mathrm{Na}_{2} \mathrm{O}\) (d) \(\mathrm{K}_{2} \mathrm{O}<\mathrm{Na}_{2} \mathrm{O}<\mathrm{Al}_{2} \mathrm{O}_{3}<\mathrm{MgO}\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.