Chapter 14: Problem 113
Which one of the following statements about halogens is incorrect? (1) The electron affinities are in order \(\mathrm{F}>\mathrm{Cl}>\mathrm{Br}>\mathrm{I}\) (2) \(\mathrm{F}_{2}\) has lower bond dissociation energy than \(\mathrm{Cl}_{2}\) (3) \(\mathrm{HF}\) is the strongest hydrothalic acid (4) Van der Waals forces are the weakest in iodine (a) 1,2 and 4 (b) 1,3 and 4 (c) 1,2 and 3 (d) 2,3 and 4
Short Answer
Step by step solution
Understand the Problem
Analyze Statement 1
Analyze Statement 2
Analyze Statement 3
Analyze Statement 4
Determine Incorrect Statements and Answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Electron Affinity
- This is due to smaller electron repulsions in chlorine's outer shell compared to fluorine's, where the compact size leads to increased electron-electron repulsion.
- The correct order is: \( \mathrm{Cl} > \mathrm{F} > \mathrm{Br} > \mathrm{I} \).
Bond Dissociation Energy
- The small size of fluorine atoms results in lone pairs that are closer together, leading to increased repulsion. This weakens the bond.
- Chlorine atoms, being larger, have less repulsion between lone pairs, resulting in stronger bonding in \( \mathrm{Cl}_2 \).
Hydrohalic Acids
- \( \mathrm{HF} \) does not dissociate completely in water because of the strong hydrogen-fluorine bond, which does not easily break.
- In contrast, \( \mathrm{HCl} \), \( \mathrm{HBr} \), and \( \mathrm{HI} \) are stronger acids because they dissociate more completely in water, releasing more hydrogen ions.