Chapter 13: Problem 167
Match the following Column-I Column-II (a) \(\mathrm{O}_{2}^{2+}\) (p) Paramagnetic (b) \(\mathrm{O}_{2}^{+}\) (q) Diamagnetic (c) \(\mathrm{O}_{2}^{-}\) (r) Bond order \(=1\) (d) \(\mathrm{O}_{2}^{2-}\) (s) Bond order \(=1.5\) (t) Stable ion under appropriate conditions in the gas or liquid phase.
Short Answer
Step by step solution
Understand the properties of molecular oxygen
Determine magnetic property (paramagnetic/diamagnetic) and bond order of each ion
Match each oxygen ion to its properties
Final matching list
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Bond Order
- For \(\mathrm{O}_{2}^{2+}\), the bond order is 3, indicating a strong bond.
- For \(\mathrm{O}_{2}^{+}\), the bond order is 2.5.
- For \(\mathrm{O}_{2}^{-}\), the bond order is 1.5.
- For \(\mathrm{O}_{2}^{2-}\), the bond order is 1, showing a weaker bond compared to oxygen with higher bond orders.
Paramagnetism
- \(\mathrm{O}_{2}^{+}\): This ion has 11 electrons with one unpaired electron, making it paramagnetic.
- \(\mathrm{O}_{2}^{-}\): Similar to \(\mathrm{O}_{2}^{+}\), it has an unpaired electron and is therefore paramagnetic as well.
Diamagnetism
- \(\mathrm{O}_{2}^{2+}\): This ion, having lost two electrons from the neutral oxygen molecule, has no unpaired electrons and is therefore diamagnetic.
- \(\mathrm{O}_{2}^{2-}\): With full filling of its molecular orbitals, \(\mathrm{O}_{2}^{2-}\) also exhibits diamagnetism as all its electrons are paired.
Oxygen Ions
Different Forms of Oxygen Ions
Oxygen typically occurs as \(\mathrm{O}_2\), but it can gain or lose electrons, forming ions such as:- \(\mathrm{O}_{2}^{2+}\): Gained by removing electrons, it is less common in nature.
- \(\mathrm{O}_{2}^{+}\): Has one less electron, making it paramagnetic.
- \(\mathrm{O}_{2}^{-}\): Acquires an extra electron and is paramagnetic as well.
- \(\mathrm{O}_{2}^{2-}\): Known as the peroxide ion, it is stable particularly under certain conditions in the liquid or gas phase.