Chapter 13: Problem 138
Match the following: List I List II (Species) (Bond order) 1\. \(\mathrm{O}_{2}^{2+}\) (i) \(1.0\) 2\. \(\mathrm{O}_{2}\) (ii) \(2.0\) 3\. \(\mathrm{F}_{2}\) (iii) \(2.5\) 4\. \(\mathrm{O}_{2}^{+}\) (iv) \(3.0\) The correct matching is: \(\begin{array}{llll}1 & 2 & 3 & 4\end{array}\) (a) (iv) (i) (ii) (ii) (b) (ii) (iii) (i) (iv) (c) (iv) (ii) (i) (iii) (d) (iii) (iv) (i) (ii)
Short Answer
Step by step solution
Understanding Bond Order
Calculating Bond Order for \(\mathrm{O}_{2}^{2+}\)
Calculating Bond Order for \(\mathrm{O}_{2}\)
Calculating Bond Order for \(\mathrm{F}_{2}\)
Calculating Bond Order for \(\mathrm{O}_{2}^{+}\)
Matching the Bond Order to Species
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Molecular Orbital Theory
- Bonding orbitals enhance stability by creating an electron cloud between nuclei, favoring attraction.
- Antibonding orbitals reduce stability with nodes that push nuclei apart.
Electron Configuration
- The principle begins with occupying lower energy bonding orbitals.
- Progresses to higher energy antibonding orbitals if more electrons need placement.
Chemical Bonding
- Higher bond order typically correlates with stronger, shorter bonds.
- Lower bond orders suggest weaker, longer bonds.
Oxygen Species
- \(O_2\) is a stable molecule with a fundamental role in respiration and combustion.
- \(O_2^+\) is less stable, existing typically in high-energy environments, such as mass spectrometry applications.
- \(O_2^{2+}\) has fewer electrons, meaning its bond order and magnetic properties differ significantly from neutral \(O_2\).
Stability of Molecules
- Species with higher bond orders are typically more energetically favorable and less reactive.
- Molecules with unpaired electrons or lower bond orders exhibit magnetic properties and higher reactivity.