Chapter 13: Problem 104
The correct order of the lattice energies for the following ionic compounds is (a) \(\mathrm{Al}_{2} \mathrm{O}_{3}>\mathrm{CaO}>\mathrm{MgBr}_{2}>\mathrm{NaCl}\) (b) \(\mathrm{MgBr}_{2}>\mathrm{Al}_{2} \mathrm{O}_{3}>\mathrm{CaO}>\mathrm{NaCl}\) (c) \(\mathrm{Al}_{2} \mathrm{O}_{3}>\mathrm{MgBr}_{2}>\mathrm{CaO}>\mathrm{NaCl}\) (d) \(\mathrm{NaCl}>\mathrm{MgBr}_{2}>\mathrm{CaO}>\mathrm{Al}_{2} \mathrm{O}_{3}\)
Short Answer
Step by step solution
Define Lattice Energy
Compare Ionic Charges
Consider Ionic Sizes
Determine Order of Lattice Energies
Identify the Correct Option
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ionic Compounds
Important factors influencing the lattice energy:
- Charge of ions: Higher charges typically lead to higher lattice energies.
- Size of ions: Smaller ions contribute to greater lattice energy because they can get closer to each other.
Charge Product
- \[ \mathrm{Al}_{2} \mathrm{O}_{3}, \] with \[ +3 imes -2 = -6,\]
- \[ \mathrm{CaO}, \] with \[ +2 \times -2 = -4,\]
- \[ \mathrm{MgBr}_{2}, \] with \[ +2 \times -1 = -2,\]
- \[ \mathrm{NaCl},\] with \[ +1 \times -1 = -1.\]
Ionic Size
Comparing ion sizes:
- \[ \mathrm{Al}^{3+} \text{ and } \mathrm{O}^{2-} \] are smaller than the other ions involved.
- \[ \mathrm{Ca}^{2+} \text{ } \] and \[ \mathrm{O}^{2-} \] form a tighter bond than larger ions.
- \[ \mathrm{Mg}^{2+}\] and \[ \mathrm{Br}^{-}\] are larger, leading to a greater distance.
- \[ \mathrm{Na}^{+} \] and \[ \mathrm{Cl}^{-}\] in \[ \mathrm{NaCl} \] have larger radii, increasing the distance.
Order of Lattice Energies
- \[ \mathrm{Al}_{2} \mathrm{O}_{3} \] stands out due to its high charge product and small ionic size.
- \[ \mathrm{CaO} \] follows, supported by a moderate charge and small ion size.
- \[ \mathrm{MgBr}_{2} \] comes next with a lesser charge impact compared to \[ \mathrm{CaO} \].
- \[ \mathrm{NaCl} \], with the least charge and larger ions, has the lowest lattice energy.