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Which ionization potential in the following equations involves the greatest amount of energy? (a) \(\mathrm{Na} \longrightarrow \mathrm{Na}^{+}+\mathrm{e}^{-}\) (b) \(\mathrm{K} \longrightarrow \mathrm{K}^{+} \mathrm{e}^{-}\) (c) \(\mathrm{Cs}^{2+} \longrightarrow \mathrm{Cs}^{3+}+\mathrm{e}^{-}\) (d) \(\mathrm{Ca}^{+} \longrightarrow \mathrm{Ca}^{2+}+\mathrm{e}^{-}\)

Short Answer

Expert verified
The reaction (c) : 鲁} 鲁+ involves the greatest energy.

Step by step solution

01

Understand Ionization Potential

Ionization potential is the energy required to remove an electron from an atom or ion. The more positively charged the ion, the higher the ionization potential required to remove another electron. This is because the electrons are held more tightly by the greater positive charge of the nucleus.
02

Analyze the given processes

Consider the ionization processes: (a) Na 鈫 Na鈦 + e鈦 (b) K 鈫 K鈦 + e鈦 (c) Cs虏鈦 鈫 Cs鲁鈦 + e鈦 (d) Ca鈦 鈫 Ca虏鈦 + e鈦. Processes (a) and (b) involve neutral atoms becoming cations, while (c) and (d) involve the removal of an electron from already positively charged ions.
03

Compare the charge states

Removing an electron from an ion with a higher positive charge requires more energy. Process (c) starts with a Cs虏鈦 ion that becomes Cs鲁鈦 by losing an electron. This requires more energy compared to process (d) where a Ca鈦 ion becomes Ca虏鈦, since Cs in process (c) starts with a higher initial charge.
04

Conclude the highest energy process

Among the given processes, removing an electron from Cs虏鈦 to form Cs鲁鈦 involves the greatest amount of energy due to the already high positive charge on Cs虏鈦. Therefore, process (c) has the highest ionization potential.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Energy Required for Electron Removal
The concept of ionization potential revolves around the idea of how much energy is needed to take an electron away from an atom or ion. In simpler terms, imagine electrons as little magnets attached to their respective atoms. To take one away, you need to "pay" energy. This energy varies depending on two factors: the size of the atom and how strongly the nucleus (the atom鈥檚 center) holds onto the electron.
  • The larger the atom, the less energy required, as the outer electrons are farther away from the nucleus.
  • Stronger nuclear pull means more energy is needed to remove the electron.

When an atom or ion is positively charged, like in our exercise, the attraction force from the nucleus strengthens. This elevates the energy required to remove any additional electrons. In essence, cracking open a positively charged ion involves a greater "energy bill." As ions gather more positive charges, the challenge鈥攁nd energy necessity鈥攊ncreases proportionally.
Ion Charge and Ionization Energy
Ion charge is pivotal when considering ionization energy. Every time you remove an electron, an atom's positive charge increases. This escalation makes it tougher each subsequent time you try to remove another electron. Let's break this down:

Initially, when an electron is removed from a neutral atom (like Na or K becoming Na鈦 or K鈦), the electron barely gets a grip from its sphere of positive influence, hence less energy is used.
  • As the positive charge rises in ion, the tightly held electrons require more energy to be dislodged.
  • The increasing positive charge amplifies the nucleus's attractive force on the remaining electrons.

In our exercise, this is evident with Cs虏鈦 needing a lot more energy to pop another electron off, transforming into Cs鲁鈦, compared to K or Na from neutral state scenarios. This speaks to the broader truth in chemistry: positive ions don鈥檛 let go of their electrons without a fight鈥攁nd that fight takes energy!
Comparing Ionization Processes
Comparing different ionization processes aids in understanding how electrons react under different circumstances. Each reaction has its distinct action and energy demands, dictated by its starting charge state. Let鈥檚 break down what this means:
  • Neutral atoms losing an electron, like Na becoming Na鈦 or K becoming K鈦, require relatively less energy because there's only the initial positive charge to contend with.
  • When ions like Cs虏鈦 or Ca鈦 lose electrons, the stakes are higher as there are existing positive charges making electron reassignment more of an uphill battle.

In our scenario, Cs虏鈦 turning into Cs鲁鈦 stands out as the most energy-intensive due to its high starting positive charge. Picks like this hint at broader trends: the more initially positive the ion, the more stubborn the remaining electrons become. It emphasizes that chemicals with higher positive charges often resist change more, ensuring they get stable even when more "electric energy currency" comes into play.

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Most popular questions from this chapter

Properties that are directly or indirectly related to the electronic configuration of the elements and show a regular gradation when we move from left to right in a period or form top to bottom in a group are called periodic properties. Some of these properties are ionization energy, electron affinity and electronegativity Which of the following is arranged in the order of decreasing electropositive character ? (a) \(\mathrm{Fe}, \mathrm{Mg}, \mathrm{Cu}\) (b) \(\mathrm{Mg}, \mathrm{Cu}, \mathrm{Fe}\) (c) \(\mathrm{Mg}, \mathrm{Fe}, \mathrm{Cu}\) (d) \(\mathrm{Cu}, \mathrm{Fe}, \mathrm{Mg}\)

The correct order of decreasing first ionization potential is (a) \(\mathrm{Ca}>\mathrm{K}>\mathrm{Rb}>\mathrm{Cs}\) (b) \(\mathrm{Cs}>\mathrm{Rb}>\mathrm{K}>\mathrm{Ca}\) (c) \(\mathrm{Ca}>\mathrm{Cs}>\mathrm{Rb}>\mathrm{K}\) (d) \(\mathrm{K}>\mathrm{Rb}>\mathrm{Cs}>\mathrm{Ca}\)

The set representing the correct order of first ionization potential is (a) \(\mathrm{K}>\mathrm{Na}>\mathrm{Li}\) (b) \(\mathrm{Br}>\mathrm{Mg}>\mathrm{Ca}\) (c) \(\mathrm{B}>\mathrm{C}>\mathrm{N}\) (d) Ge \(>\mathrm{Si}>\mathrm{C}\)

In the following, the element with the highest ionization energy is (a) \([\mathrm{Ne}] 3 \mathrm{~s}^{2} 3 \mathrm{p}^{1}\) (b) \([\mathrm{Ne}] 3 \mathrm{~s}^{2} 3 \mathrm{p}^{3}\) (c) \([\mathrm{Ne}] 3 \mathrm{~s}^{2} 3 \mathrm{p}^{2}\) (d) \([\mathrm{Ne}] 3 \mathrm{~s}^{2} 3 \mathrm{p} 4\)

The electron affinities of \(\mathrm{N}, \mathrm{O}, \mathrm{S}\) and \(\mathrm{Cl}\) are (a) \(\mathrm{O} \approx \mathrm{Cl}<\mathrm{N} \approx \mathrm{S}\) (b) \(\mathrm{O}<\mathrm{S}<\mathrm{Cl}<\mathrm{N}\) (c) \(\mathrm{N}<\mathrm{O}<\mathrm{S}<\mathrm{Cl}\) (d) \(O<\mathrm{N}<\mathrm{Cl}<\mathrm{S}\)

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