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The rate of a chemical reaction doubles for every \(10^{\circ} \mathrm{C}\) rise of temperature. If the temperature is raised by \(50^{\circ} \mathrm{C}\), the rate of the reaction increases by about: (a) 16 times (b) 42 times (c) 32 times (d) 20 times

Short Answer

Expert verified
The rate of the reaction increases 32 times.

Step by step solution

01

Understanding the Doubling Rate

The problem states that the rate of a chemical reaction doubles for every increase of \(10^{\circ} \mathrm{C}\) in temperature. This means if the rate of the reaction at an initial temperature \(T\) is \(R\), at \(T+10^{\circ} \mathrm{C}\), the rate will be \(2R\), at \(T+20^{\circ} \mathrm{C}\), it will be \(4R\), and so on.
02

Calculating the Total Increase

We are asked to determine how much the rate increases when the temperature is raised by \(50^{\circ} \mathrm{C}\). Since \(50^{\circ} \mathrm{C}\) is 5 intervals of \(10^{\circ} \mathrm{C}\), and the rate doubles every \(10^{\circ} \mathrm{C}\), the rate after \(50^{\circ} \mathrm{C}\) will be \(R \times 2^5\).
03

Performing Arithmetic

Calculate \(2^5\). This means multiplying 2 by itself 5 times: \(2 \times 2 \times 2 \times 2 \times 2=32\). This shows that the rate of the reaction increases 32 times when the temperature is raised by \(50^{\circ} \mathrm{C}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Effect of Temperature on Reaction Rate
The rate of chemical reactions is significantly influenced by temperature changes. Generally, increasing the temperature speeds up reactions. This happens because more heat provides reactant molecules with additional energy. This energy boosts their motion, leading to more frequent and forceful collisions. Thus, the likelihood of successful interactions increases. - Higher temperatures provide energy that breaks bonds, creating active species that lead to products. - More collisions occur, raising the chance of interactions that reach the necessary activation energy. - Activation energy is the minimum energy threshold needed for a reaction to proceed. Not all reactions are equally sensitive to temperature changes. Some exhibit dramatic increases in rate with a small rise in temperature, while others are less affected. This relationship between temperature and reaction speed is often quantified through the Arrhenius equation, which describes how reaction rate constants vary with temperature.
Doubling Rate
When a problem states that the reaction rate doubles for every increase of 10°C, it's describing a common temperature-dependent behavior in kinetics. For instance: - Start at an initial rate of R at temperature T. - Increase by 10°C, the rate becomes 2R. - With another 10°C increase, it shifts to 4R. This is because for every 10°C rise, the rate multiplies by two. Over five intervals of 10°C, the total rate increase follows the sequence of 2, 4, 8, 16, and finally, 32 times the original rate. This "Doubling Rate" rule is a simplified representation but reflects the acceleration often observed experimentally in many reactions within a moderate temperature range. It helps predict the effects of temperature shifts quickly without detailed calculations.
Temperature and Reaction Kinetics
In chemical kinetics, temperature is a critical factor influencing reaction rates. Higher temperatures not only increase reaction rates but also alter the mechanism of reactions in some cases. The Arrhenius equation is a fundamental relation that provides a mathematical explanation:\[ k = A e^{-E_a / (RT)} \]- \(k\) is the rate constant, linked to how fast the reaction occurs.- \(A\) is the pre-exponential factor, indicating the frequency of collisions.- \(E_a\) is the activation energy, the barrier that needs to be overcome.- \(R\) represents the gas constant.- \(T\) is the absolute temperature in Kelvin.As temperature rises, \(T\) increases, which reduces the fraction \(E_a / (RT)\) in the equation's exponent. This reduction leads to a larger value of \(k\), reflecting how the rate accelerates. By understanding this relationship, scientists and engineers can optimize conditions for desired reaction speeds, enhancing efficiency in various industries.

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Most popular questions from this chapter

In a first-order reaction the concentration of reactant decreases from \(800 \mathrm{~mol} / \mathrm{dm}^{3}\) to \(50 \mathrm{~mol} / \mathrm{dm}^{3}\) in \(2 \times 10^{4}\) sec. The rate constant of reaction in \(\mathrm{sec}^{-1}\) is (a) \(2 \times 10^{4}\) (b) \(3.45 \times 10^{-5}\) (c) \(1.386 \times 10^{-4}\) (d) \(2 \times 10^{-4}\)

Which of the following statements are correct about half-life period? (1) time required for \(99.9 \%\) completion of a reaction is 100 times the half-life period (2) time required for \(75 \%\) completion of a first-order reaction is double the half-life of the reaction (3) average life \(=1.44\) times the half-life for firstorder reaction

The decay constant of \({ }_{6} \mathrm{C}^{14}\) is \(2.31 \times 10^{-4}\) year \(^{-1}\). Its half life is (a) \(2 \times 10^{3}\) yrs (b) \(2.5 \times 10^{3} \mathrm{yrs}\) (c) \(3 \times 10^{3} \mathrm{yrs}\) (d) \(3.5 \times 10^{3} \mathrm{yrs}\)

The rate law for the reaction \(\mathrm{RCl}+\mathrm{NaOH}(\mathrm{aq}) \longrightarrow \mathrm{ROH}+\mathrm{NaCl}\) is given by Rate \(=k[\mathrm{RCl}]\). The rate of the reaction will be (a) doubled on doubling the concentration of sodium hydroxide (b) halved on reducing the concentration of alkyl halide to one half (c) decreased on increasing the temperature of reaction (d) unaffected by increasing the temperature of the reaction.

The molecularity of a reaction is (a) always two (b) same as its order (c) different than the other (d) may be same or different as compared to order

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