Chapter 10: Problem 159
The half life \(\left(\mathrm{t}_{1}\right)\) of the first order reaction and half life \(\left(t_{2}\right)\) of the second order reaction are in the ratio \(2: 1\). Hence the ratio of the rates of the above first and second order reactions at the start is (a) \(1: 0.4365\) (b) \(0.3465: 1\) (c) \(2: 1\) (d) \(1: 2\)
Short Answer
Step by step solution
Understand Half-Life Formulas
Apply Given Ratio to Half-Life Equations
Simplify the Ratio Equation
Solve for the Ratio of Rate Constants
Identify the Answer from Options
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
First-order reaction
- \( t_{1/2} \) is the half-life,
- \( k_1 \) is the rate constant of the reaction.
Second-order reaction
- \( t_{1/2} \) is the half-life,
- \( k_2 \) is the rate constant,
- \([A]_0\) is the initial concentration of the reactant.
Rate constant
- \( k_1 \) is the rate constant for first-order reactions, characterizing how quickly these reactions proceed.
- \( k_2 \) is the rate constant for second-order reactions, determining their specific reaction speeds.