Chapter 9: Problem 73
Specific conductance of \(0.01 \mathrm{~N}\) solution of an electrolyte is \(0.00419 \mathrm{mho} \mathrm{cm}^{-1} .\) The equivalent conductance of this solution will be (a) \(4.19 \mathrm{mho} \mathrm{cm}^{2}\) (b) \(419 \mathrm{mho} \mathrm{cm}^{2}\) (c) \(0.0419\) mho \(\mathrm{cm}^{2}\) (d) \(0.209 \mathrm{mho} \mathrm{cm}^{2}\)
Short Answer
Step by step solution
Identifying Given Values
Formula for Equivalent Conductance
Substitute Given Values
Calculate the Equivalent Conductance
Compare with Options
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Specific Conductance
- The ions in the solution move when an electric field is applied. This movement creates an electric current.
- The more ions present, and the more mobile they are, the higher the current that can be conducted.
Defining Normality in Electrolyte Solutions
- A solution with normality of 0.01 N means there are 0.01 equivalents of solute per liter.
- For acids like sulfuric acid (H2SO4), each mole supplies two equivalents because it donates two protons (H+ ions).
What is an Electrolyte Solution?
- They conduct electricity due to ionic movement.
- The strength of an electrolyte (strong vs. weak) depends on its ability to dissociate into ions. Strong electrolytes fully dissociate while weak electrolytes partially do.
Conductivity Calculations: Breaking It Down
- ba (belectrolytic conductivity) is specific conductance, given in mho cm-1.
- C is the concentration in normality.
- Identify the given specific conductance and normality.
- Plug these into the formula.
- Perform the division to get the result.