Chapter 8: Problem 176
A buffer solution is prepared by mixing \(20 \mathrm{ml}\) of \(0.1 \mathrm{M}\) \(\mathrm{CH}_{3} \mathrm{COOH}\) and \(40 \mathrm{ml}\) of \(0.5 \mathrm{M} \mathrm{CH}_{3} \mathrm{COONa}\) and then diluted by adding \(100 \mathrm{ml}\) of distilled water. The \(\mathrm{pH}\) of resulting buffer solution is (Given \(\mathrm{pKa} \mathrm{CH}_{3} \mathrm{COOH}=4.76\) ) (a) \(5.76\) (b) \(4.67\) (c) \(3.48\) (d) \(5.9\)
Short Answer
Step by step solution
Calculate Initial Moles of Substances
Calculate Final Concentrations After Dilution
Apply Henderson-Hasselbalch Equation
Calculate the pH
Verify the Answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Henderson-Hasselbalch Equation
- \[ \text{pH} = \text{pKa} + \log \left( \frac{[\text{A}^-]}{[\text{HA}]} \right) \]
Acetic Acid
Sodium Acetate
pH Calculation
- First, determine the ratio of the concentrations of the conjugate base to the weak acid.
- Next, apply the equation: \[ \text{pH} = \text{pKa} + \log \left( \frac{0.125}{0.0125} \right) \]
- Solve the logarithmic component: \( \log(10) = 1 \).
- The final computation yields a pH of 5.76.